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 BeautifulSoup4, How to get an HTML tag with specific class.
#1
I have HTML code like the following from a URL:
<img class="this" alt="this" src="this_source1.gif">
<img class="this" alt="this" src="this_source2.gif">
<img class="this" alt="this" src="this_source3.gif">
<img class="this and that" alt="not this" src="this__and_that_source1.gif">
<img class="this and that" alt="not this" src="this__and_that_source2.gif">
<img class="this and that" alt="not this" src="this__and_that_source3.gif">

I'm trying to get the alt value of just the img tags with only class="this"

import requests
from bs4 import BeautifulSoup
url = "https://someurl.com"
resp = requests.get(url)
txt = resp.text
soup = BeautifulSoup(txt, 'lxml')
imgThis = soup.find_all('img', class_='this')
for i in (imgThis):
	imgThis[i]['alt']
The find_all method returns alts for both class_="this" and class_="this and that"

How do I specify only to return class_="this"?
Quote
#2
I have HTML code like the following from a URL:
<img class="this" alt="this" src="this_source1.gif">
<img class="this" alt="this" src="this_source2.gif">
<img class="this" alt="this" src="this_source3.gif">
<img class="this and that" alt="not this" src="this__and_that_source1.gif">
<img class="this and that" alt="not this" src="this__and_that_source2.gif">
<img class="this and that" alt="not this" src="this__and_that_source3.gif">

I'm trying to get the alt strings of img tags with specifically class="this"

import requests
from bs4 import BeautifulSoup
url = 'https://someurl.com'
resp = requests.get(url)
txt = resp.text
soup = BeautifulSoup(txt, 'lxml')
imgThis = soup.find_all('img', class_='this')
for i in (imgThis):
	imgThis[i]['alt']
The find_all method returns matches for both class_="this" and class_="this and that"

Output:
this
this
this
this and that
this and that
this and that
How do I specify only to return class_="this"?
Quote
#3
for example,
<img class="this" alt="this" src="this_source1.gif">
use:
    source1 = soup.find('img', {'class': 'this'})
Quote
#4
Thank you Larz.

I did try:

test = soup.find('img', {'class': 'this'})
But that returned just the first instance of <img class="this
Which happened to be a <img class="this and that"

and
test = soup.find_all('img', {'class': 'this'})
[python]

returns all img tags with class="this" and class="this and that"
[hr]
and
[python]
test = soup.find_all('img', {'class': 'this'})
returns all img tags with class="this" and class="this and that"

...and

test = soup.find_all('img', {'class': 'this'})
returns all img tags with class="this" and class="this and that"
Quote
#5
If you really must use bs4, I would use its CSS selector support and stay away from the weird find/find_all api.
This is one way to achieve what you want:
soup.select('img[class="this"]')
In general, I'd recommend using lxml instead of bs4 for pretty much anything.
Quote
#6
Thanks stranac!

That seems to have done the trick.

It's a shame the BeautifulSoup documentation is less than optimal!
Quote
#7
Edit this is merge of Threads,so my answer is same as @stranac.
-----
Can use CSS selectors to match the exact class name.
from bs4 import BeautifulSoup

html = '''\
<img class="this" alt="this" src="this_source1.gif">
<img class="this" alt="this" src="this_source2.gif">
<img class="this" alt="this" src="this_source3.gif">
<img class="this and that" alt="not this" src="this__and_that_source1.gif">
<img class="this and that" alt="not this" src="this__and_that_source2.gif">
<img class="this and that" alt="not this" src="this__and_that_source3.gif">'''

soup = BeautifulSoup(html, 'lxml')
only_this = soup.select('img[class="this"]')
Test:
>>> only_this
[<img alt="this" class="this" src="this_source1.gif"/>,
 <img alt="this" class="this" src="this_source2.gif"/>,
 <img alt="this" class="this" src="this_source3.gif"/>]

>>> [i.get('src') for i in only_this]
['this_source1.gif', 'this_source2.gif', 'this_source3.gif']
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