Calling function-- how to call simply return value, not whole process

[juliabrushett]

Hello,

The program I am creating will take in a value produced by the user and output both that value and the square of the value. I am to use functions for both intaking and squaring the value. However, my output returns the "Enter a number: " statement twice, leading me to believe that when I invoke the getValue() function in my "The square of the value is " statement in main I am calling beyond the value and going for the whole process of getValue. How do I forego this and simply return the value? Output is as follows currently, code below:

Enter a value: 2
The value entered is 2
Enter a value: 2
The square of the value is 4

def getValue():
    val = int(input("Enter a number: "))
    return val
def squareValue():
    val = getValue()

    square = val * val
    return square

print("The value entered is", getValue())
print("The value squared is", squareValue())

[ichabod801]

It asks for a value twice because you call getValue twice. First it is called on line 10. Then on line 11 you call squareValue. The squareValue function calls getValue again on line 5.

The easy way to fix this is to remove line 10. Then you only call it once.

If you want to retain the output on line 10, there are a few ways to do it. I would suggest first changing squareValue so it accepts val as a parameter:

def squareValue(val):
    square = val * val
    return square

Then change the last couple lines to save the value from getValue and pass it to squareValue:

value = getValue()
print("The value entered is", value)
print("The value squared is", squareValue(value))

[juliabrushett]

I figured it out! Can't believe I forgot to put the value in the formal parameters:/