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 Can I evaluate a Chebyshev polynomial using a function player1681 Unladen Swallow Posts: 3 Threads: 2 Joined: Nov 2019 Reputation: 0 Likes received: 0 #1 Nov-21-2019, 08:19 AM Hello everyone. I need to evaluate an arbitrary Chebyshev polynomial of order n at a point x. I have done it manually using their definition as `mt.cos(n*mt.acos(x))`However, I am not satisfied by the numerical precision of this, the results are not exact. I have searched the web for a function that does this in a more efficient way and the closest thing I have found is the Chebyshev module. However, inside of it I cannot find what I am looking for. The first Chebyshev polynomials are P_0=1, P_1=x,P_2=2x^2-1 and so on. I need a function which output is the polynomial of the selected order evaluated at an arbitrary point. i.e. f(n=1, x=0.6)= 0.6, f(n=2, x=0.5)= 2*(0.5)^2-1 and so on. Can someone tell me if said function exists? Thanks. scidam Posts: 582 Threads: 1 Joined: Mar 2018 Reputation: 74 Likes received: 89 #2 Nov-22-2019, 06:33 AM Take a look at SymPy module. This is package for symbolic computations and computations with high precision. « Next Oldest | Next Newest »

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