Cryptography Problem

[wavic]

Why you open a new topic?

[PYTHONEUR]

Hi Wavic

Yes i know i have ubuntu in linux but my ubuntu/linux system are break like python :(

So no Python scripts

---

Thanks for the explanation I have a little better advanced, but now I encounter another problem how to convert correctly into letter?

In the example below I use ord to convert to a letter

Msg ="MATHS"
 
def num (caractere): 
    return ord (caractere)-65
 
def lettre (n):
     return  n + ord(65)
   
for c in Msg :
    print (c,end="|")
print()
for c in Msg :
     print(num(c), end=" | ")
print ('\n\n', 'le message est sous forme de chiffres')
for c in Msg: 
    print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')
     
    # Finir Cle
    
    print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')
    
A = 11
B = 7
 
 
for c in Msg:
    r=(A*(ord(c)-65)+ B)%26 + 65
    print(r, end=" | " )
for c in Msg:    
    print(lettre(r), end=" | ")

---

Thanks for the explanation I have a little better advanced, but now I encounter another problem how to convert correctly into letter?

In the example below I use ord to convert to a letter

Msg ="MATHS"
 
def num (caractere): 
    return ord (caractere)-65
 
def lettre (n):
     return  n + ord(65)
   
for c in Msg :
    print (c,end="|")
print()
for c in Msg :
     print(num(c), end=" | ")
print ('\n\n', 'le message est sous forme de chiffres')
for c in Msg: 
    print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')
     
    # Finir Cle
    
    print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')
    
A = 11
B = 7
 
 
for c in Msg:
    r=(A*(ord(c)-65)+ B)%26 + 65
    print(r, end=" | " )
for c in Msg:    
    print(lettre(r), end=" | ")

---

Now i have a new prob :

TypeError: ord() expected string of length 1, but int found

---

Forget all that I have said now, why i have that valor :

"nA"

---

Hi Wavic Yes i know i have ubuntu in linux but my ubuntu/linux system are break like python :(


So no Python scripts

Thanks for the explanation I have a little better advanced, but now I encounter another problem how to convert correctly into letter?

I have that valor : "nA"

---

---

Now i have a new prob : TypeError: ord() expected string of length 1, but int found

---

Forget all that I have said now, why i have that valor : "nA"

---

Hi Wavic Yes i know i have ubuntu in linux but my ubuntu/linux system are break like python :( So no Python scripts Thanks for the explanation I have a little better advanced, but now I encounter another problem how to convert correctly into letter? I have that valor : "nA"

---

Sorry for the spam :(

i can't delete all this...



Ok but where i can see the letters :( : 

Msg ="MATHS"
 
def num (caractere): 
    return ord (caractere)-65
 
def lettre (n):
    return  chr(n)
     
for c in Msg :
    print (c,end="|")
print()
for c in Msg :
     print(num(c), end=" | ")
print ('\n\n', 'le message est sous forme de chiffres')
for c in Msg: 
    print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')
     
    # Finir Cle
    
    print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')
    
A = 11
B = 7
 
 
for c in Msg:
    r=  (A*(ord(c)-65)+ B)%26 + 65
    print(r , end=" | " )

for c in Msg :
    R = r-65
    print(lettre(R), end= " | " )
    
   

   

---

Hi Wavic Yes i know i have ubuntu in linux but my ubuntu/linux system are break like python :( So no Python scripts

---

Thanks for the explanation I have a little better advanced, but now I encounter another problem how to convert correctly into letter? In the example below I use ord to convert to a letter

Msg ="MATHS"   def num (caractere):      return ord (caractere)-65   def lettre (n):      return  n + ord(65)     for c in Msg :     print (c,end="|") print() for c in Msg :      print(num(c), end=" | ") print ('\n\n', 'le message est sous forme de chiffres') for c in Msg:      print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')           # Finir Cle          print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')      A = 11 B = 7     for c in Msg:     r=(A*(ord(c)-65)+ B)%26 + 65     print(r, end=" | " ) for c in Msg:         print(lettre(r), end=" | ") 

---

Thanks for the explanation I have a little better advanced, but now I encounter another problem how to convert correctly into letter? In the example below I use ord to convert to a letter

Msg ="MATHS"   def num (caractere):      return ord (caractere)-65   def lettre (n):      return  n + ord(65)     for c in Msg :     print (c,end="|") print() for c in Msg :      print(num(c), end=" | ") print ('\n\n', 'le message est sous forme de chiffres') for c in Msg:      print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')           # Finir Cle          print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')      A = 11 B = 7     for c in Msg:     r=(A*(ord(c)-65)+ B)%26 + 65     print(r, end=" | " ) for c in Msg:         print(lettre(r), end=" | ") 

---

Now i have a new prob : TypeError: ord() expected string of length 1, but int found

---

Forget all that I have said now, why i have that valor : "nA"

---

Hi Wavic Yes i know i have ubuntu in linux but my ubuntu/linux system are break like python :( So no Python scripts Thanks for the explanation I have a little better advanced, but now I encounter another problem how to convert correctly into letter? I have that valor : "nA"

---

---

Now i have a new prob : TypeError: ord() expected string of length 1, but int found

---

Forget all that I have said now, why i have that valor : "nA"

---

Hi Wavic Yes i know i have ubuntu in linux but my ubuntu/linux system are break like python :( So no Python scripts Thanks for the explanation I have a little better advanced, but now I encounter another problem how to convert correctly into letter? I have that valor : "nA"

---

Sorry for the spam :( i can't delete all this... Ok but where i can see the letters :( : 

Msg ="MATHS"   def num (caractere):      return ord (caractere)-65   def lettre (n):     return  chr(n)       for c in Msg :     print (c,end="|") print() for c in Msg :      print(num(c), end=" | ") print ('\n\n', 'le message est sous forme de chiffres') for c in Msg:      print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')           # Finir Cle          print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')      A = 11 B = 7     for c in Msg:     r=  (A*(ord(c)-65)+ B)%26 + 65     print(r , end=" | " ) for c in Msg :     R = r-65     print(lettre(R), end= " | " )             

[PYTHONEUR]

There is a lot of bugs, it's the new

---

Here the new code, but why i can't see the letters

i use 

[return  chr(int(65)) + n/python]


[python]Msg ="MATHS"
 
def num (caractere): 
    return ord (caractere)-65
 
def lettre (n):
    return  chr(int(65)) + n
     
for c in Msg :
    print (c,end="|")
print()
for c in Msg :
     print(num(c), end=" | ")
print ('\n\n', 'le message est sous forme de chiffres')
for c in Msg: 
    print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')
     
    # Finir Cle
    
    print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')
    
A = 11
B = 7
 
 
for c in Msg:
    r=  (A*(ord(c)-65)+ B)%26 
    print(r , end=" | " )

for c in Msg :

    print(lettre(r), end= " | " )
    
   

   

---

There is a lot of bugs, it's the new

---

Here the new code, but why i can't see the letters i use

[return  chr(int(65)) + n/python] [python]Msg ="MATHS"   def num (caractere):      return ord (caractere)-65   def lettre (n):     return  chr(int(65)) + n       for c in Msg :     print (c,end="|") print() for c in Msg :      print(num(c), end=" | ") print ('\n\n', 'le message est sous forme de chiffres') for c in Msg:      print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')           # Finir Cle          print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')      A = 11 B = 7     for c in Msg:     r=  (A*(ord(c)-65)+ B)%26      print(r , end=" | " ) for c in Msg :     print(lettre(r), end= " | " )             

---

Delete the first line of the code

[wavic]

Output:
victor@jerry:~$ python3 test.py
M|A|T|H|S|
12 | 0 | 19 | 7 | 18 | 

 le message est sous forme de chiffres


 Maintenant veuillez entrer deux chiffres pour créer votre cles 


 soit la fonction affine a*x + b qui va vous permettre de créer votre cles 


 Maintenant veuillez entrer deux chiffres pour créer votre cles 


 soit la fonction affine a*x + b qui va vous permettre de créer votre cles 


 Maintenant veuillez entrer deux chiffres pour créer votre cles 


 soit la fonction affine a*x + b qui va vous permettre de créer votre cles 


 Maintenant veuillez entrer deux chiffres pour créer votre cles 


 soit la fonction affine a*x + b qui va vous permettre de créer votre cles 


 Maintenant veuillez entrer deux chiffres pour créer votre cles 


 soit la fonction affine a*x + b qui va vous permettre de créer votre cles 
74 | 72 | 73 | 71 | 88 |  |  |  |  |  |

This is what I get as output. Which letters you can't see? Between | | | | | |? This is because the scripts returns a nonprintable characters.
[Image: dytd6b]

Also, the 'r' will contain the last value from the previous for loop

[PYTHONEUR]

((Please don't delet this post Delet the others))

Sorry for the spam :(

Here the code you can test it in this site : http://www.pythontutor.com/visualize.html#mode=display

Always the pro with chr and ord

Msg ="MATHS"
 
def num (caractere): 
    return ord (caractere)-65
 
def lettre (n):
    return  chr(n)
     
for c in Msg :
    print (c,end="|")
print()
for c in Msg :
     print(num(c), end=" | ")
print ('\n\n', 'le message est sous forme de chiffres')
for c in Msg: 
    print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')
     
    # Finir Cle
    
    print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')
    
A = 11
B = 7
 
 
for c in Msg:
    r=  (A*(ord(c)-65)+ B)%26 
    print(r , end=" | " )
    
for c in Msg:
    print(lettre(r), end= " | " )

   

   
 
   

[metulburr]

Merged your 3 threads together. And deleted the other duplicate threads. Please dont make a new thread every time your code changes slightly. Also dont remove post content and replace it with nothing. Please refer to our help documents for our rules.

[PYTHONEUR]

Guys i have this new code

Why i can't see the letters, if think it's again chr in line 5

[/Msg ="MATHS"
 
def num (caractere): 
    return ord (caractere)-65
 
def lettre (n):
    return  chr(r)
     
for c in Msg :
    print (c,end="|")
print()
for c in Msg :
     print(num(c), end=" | ")
print ('\n\n', 'le message est sous forme de chiffres')
for c in Msg: 
    print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')
     
    # Finir Cle
    
    print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')
    
A = 11
B = 7
 
 
for c in Msg:
    r=  (A*(ord(c)-65)+ B)%26 
    print(r , end=" | " )
    
for c in Msg:
    print(lettre(r), end= " | " )

   

   
   

   

---

Guys i have this new code Why i can't see the letters, if think it's again chr in line 5

[/Msg ="MATHS"   def num (caractere):      return ord (caractere)-65   def lettre (n):     return  chr(r)       for c in Msg :     print (c,end="|") print() for c in Msg :      print(num(c), end=" | ") print ('\n\n', 'le message est sous forme de chiffres') for c in Msg:      print ( '\n\n','Maintenant veuillez entrer deux chiffres pour créer votre cles ')           # Finir Cle          print ('\n\n', 'soit la fonction affine a*x + b qui va vous permettre de créer votre cles ')      A = 11 B = 7     for c in Msg:     r=  (A*(ord(c)-65)+ B)%26      print(r , end=" | " )      for c in Msg:     print(lettre(r), end= " | " )                

[wavic]

As I said, 'r' holds the last value from the previous for loop. This one:

for c in Msg:
    r=  (A*(ord(c)-65)+ B)%26 
    print(r , end=" | " )

In the next wor loop 'r' will contain one value each iteration. If it is nonpritable character, as it seems to be, you would't see anything in the output

[Larz60+]

Larz60+ Wrote: es i use python On-line, i don't have python because i have Ubuntu

No I did not write this

[PYTHONEUR]

Ok, but what should i do for "r" ?

int ? int® but i didn't work

str i don't know...

---

So i change it into this : Still the same problem 

or c in Msg:
    r=  (A*(ord(c)-65)+ B)%26 
    print(lettre(r), end= " | " )