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Help with calling list from user input
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Help with calling list from user input
#1
I am new to python and need help. I tried to call the list using an input from the user but I got creating a new list instead of calling the existing one. Here is the previous code:

aa = input("please enter the 3 letter amino acid to view the codon: ")
print(list(aa))

Then I used multiple "if" statement to solve it but I think there is a better way to solve it. Please help me if you have better way or a suggestion for more efficient code, I really appreciate it. Here is the code I wrote:

phe = ["UUU", "UUC"]
leu = ["UUA", "UUG", "CUU", "CUC", "CUA", "CUG"]
ile = ["AUU", "AUC", "AUA"]
met = ["AUG"]
val = ["GUU", "GUC", "GUA", "GUG"]
ser = ["UCU", "UCC", "UCA", "UCG"]
pro = ["CCU", "CCC", "CCA", "CCG"]
thr = ["ACU", "ACC", "ACA", "ACG"]
ala = ["GCU", "GCC", "GCA", "GCG"]
tyr = ["UAU", "UAC"]
stop = ["UAA", "UAG", "UGA"]
his = ["CAU", "CAC"]
gln = ["CAA", "CAG"]
asn = ["AAU", "AAC"]
lys = ["AAA", "AAG"]
asp = ["GAU", "GAC"]
glu = ["GAA", "GAG"]
cys = ["UGU", "UGC"]
trp = ["UGG"]
arg = ["CGU", "CGC", "CGA", "CGG", "AGA", "AGG"]
ser = ["AGU", "AGC"]
gly = ["GGU", "GGC", "GGA", "GGG"]
print("Welcome to Amino Acid sequence Codon")
print()
while 1==1:
    aa = input("please enter the 3 letter amino acid to view the codon: ")
    if aa == "phe":
        print(list(phe))
    if aa == "leu":
        print(list(leu))
    if aa == "ile":
        print(list(ile))
    if aa == "met":
        print(list(met))
    if aa == "val":
        print(list(val))
    if aa == "ser":
        print(list(ser))
    if aa == "pro":
        print(list(pro))
    if aa == "thr":
        print(list(thr))
    if aa == "ala":
        print(list(ala))
    if aa == "tyr":
        print(list(tyr))
    if aa == "stop":
        print(list(stop))
    if aa == "his":
        print(list(his))
    if aa == "gln":
        print(list(gln))
    if aa == "asn":
        print(list(asn))
    if aa == "lys":
        print(list(lys))
    if aa == "asp":
        print(list(asp))
    if aa == "glu":
        print(list(glu))
    if aa == "cys":
        print(list(cys))
    if aa == "trp":
        print(list(trp))
    if aa == "arg":
        print(list(arg))
    if aa == "gly":
        print(list(gly))
    quit=input("Quit: y/n? ")
    if quit == "y":
        break
    if quit == "n":
        continue
    else:
        print("error")
        break
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Messages In This Thread
Help with calling list from user input - by farispython - Nov-03-2019, 07:22 AM

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