How can I produce a list of n times the same element?

[JoeB]

I want to produce the list: ["*", "*", "*", "*", "*"].

Can this be done in a simple line? (I don't want to have to create a function to do it.)

So far I have been having to do the following, which is very inconvenient and tedious:

v = []
for i in xrange(5):
    v.append("*")

[Larz60+]

 v = ('* '*5).split()

result:

Output:
>>> v
['*', '*', '*', '*', '*']

[JoeB]

 v = ('* '*5).split()

result:

Output:
>>> v
['*', '*', '*', '*', '*']

Thanks. How come it doesn't work to then append to v?
So for example:

v = ('* '*5).split()
print v.append("*")

gives an output of

Output:
None

[snippsat]

You code as list comprehensions.

>>> v = ['*' for i in range(5)]
>>> v
['*', '*', '*', '*', '*']

Or:

>>> v = ['*']  * 5
>>> v
['*', '*', '*', '*', '*']

[Larz60+]

I can do it with the one i wrote:

>>> v = ('* '*5).split()
>>> v
['*', '*', '*', '*', '*']
>>> v.append('-')
>>> v
['*', '*', '*', '*', '*', '-']
>>>

[nilamo]

list.append() will append the item, but it returns None.  Since you're print()ing the return value of list.append(), that's why you see None.

[wavic]

v = ["*"] * 5