How do I get rid of certain text

[keegan_010]

Hello, I am pretty new to python and wanted to make a simple program that tells you how long you have been alive for. All I have so far is:

import datetime

day = int(input ("What day were you born e.g '30'/10/2003."))
month = int(input ("What month were you born e.g 30/'10'/2003."))
year = int(input ("What year were you born e.g 30/10/'2003'."))

days = datetime.datetime.now() - datetime.datetime(year, month, day)

print (days)

However, when I do this, it ends up doing this:

Output:
What day were you born e.g '30'/10/2003.18
What month were you born e.g 30/'10'/2003.08
What year were you born e.g 30/10/'2003'.1999
6936 days, 19:07:59.588134

Does anyone know how I can get rid of the time at the end?

Thanks in Advance.

[j.crater]

Hello, try with:

print (days.days)

days is also name of a timedelta object property. To avoid confusion and potential errors, I advise you to use a different variable name for days (in line 7).

[perfringo]

Some observations:

'Explicit is better than implicit': datetime.datetime.today() says explicitly that I am interested in (to)day. datetime.datetime.now() says implicitly that I am interested in current point of time. You will have correct number of days in both ways but it's zen to signal your intentions explicitly.

Your current way of taking input from user can be optimized. You can ask input once and parse date from that without converting input. There is strptime (string-parse-time) method in datetime. You can do this way:

>>> answer = input('Please enter your birthday in dd/mm/yyyy format: ')
Please enter your birthday in dd/mm/yyyy format:  01/01/2000
>>> birthdate = datetime.datetime.strptime(answer, '%d/%m/%Y')
>>> (datetime.datetime.today() - birthdate).days
6801

You will get ValueError if user input is not in correct format.