How to check if user entered string or integer or float??

[prateek3]

I am solving a basic example using while loop in which user enters a number and program prints a countdown from that number to zero. But the catch is that program will inform you if user enters an unexpected number or string. For checking if input number in an integer i use //a = isinstance(x, int)//. The program is working only for condition if i enter a negative integer but not executing else statement when i entered float or string.

x=int(input("Enter a positive integer for countdown"))
print(x)
a = isinstance(x, int)
if a==True and x>=0:
    while x!=0:
        x-=1
        print(x)
else:
    print("Please enter a positive integer")

[Windspar]

def main():
    while True:
        x = input("Enter number >> ")
        if x.isdigit():
            if int(x) >= 0:
                break
        elif x.count('.') == 1:
            if x.replace('.','').isdigit():
                print(x)
                break

        print("Please enter a positive integer.")

main()

---

or

def isint(n):
    try:
        int(n)
        return True
    except:
        return False

def isfloat(n):
    try:
        float(n)
        return True
    except:
        return False

def main():
    while True:
        x = input("Enter number >> ")
        if isint(x):
            if int(x) >= 0:
                print("int", x)
                break
        elif isfloat(x):
                print("float", x)
                break

        print("Please enter a positive integer.")

main()

[Larz60+]

Just a side thought, you might want to create a decorator that uses assertions to check your input,
'when you have some spare time', something to pt on the todo list:
https://stackoverflow.com/questions/1529...-arguments

[DeaD_EyE]

Don't ask for permission, ask for forgiveness. The try-except is the best example.
Just look how many different representations floats could have:

1.
.0
1e1
1e-1
1e+1
1.1e-1
1.1e+1
.1e+1
nan
inf

[prateek3]

Sorry, i didn't get your point

[DreamingInsanity]

Sorry, i didn't get your point

userInput = input ("Enter the number")
try:
num = int(userInput)
print("The interger is", num)
except ValueError:
try:
num = float(userInput)
print("The float number is ", num)
except ValueError:
print("It is not a interger or a float")

for more info [URL DELETED]

It's a two year old post, the OP got the answer they needed, and your code isn't in code blocks - was it worth it?