How to get parent directory from existing func not user func ?

[harun2525]

i know we can make us own function for do this with several os.path functions. but if there is a any existing function for do this, i want to use it

get_parent_dir("/path/to/myapp/modules") # returns => '/path/to/myapp/'

---

my solution is

parentdir = lambda path: os.path.realpath(path + "/.." )

[nilamo]

Pathlib is the True Savior of All Things Path:

>>> import pathlib as plib
>>> x = plib.Path("/path/to/myapp/modules")
>>> print(x.parent)
\path\to\myapp
>>> x.parent
WindowsPath('/path/to/myapp')

[Larz60+]

You can the parent of a function with inspect:

This combined with Nilamo's code could be the start of a useful way to create program flow graphically.

import inspect

def function1():
   print('Function1 called from: {}'.format(inspect.stack()[1][3]))

def function3():
   print('Function1 called from: {}'.format(inspect.stack()[1][3]))
   function1()

def function2():
   print('Function2 called from: {}'.format(inspect.stack()[1][3]))
   function3()

def main():
   function2()


if __name__ == '__main__':
   main()

results:

Output:
Function2 called from: main
Function1 called from: function2
Function1 called from: function3

Process finished with exit code 0

[harun2525]

thanks for answers.