How to print the 2nd column of a searched string in a csv

[ptey07]

Hi there can someone help

i am trying to search for a file name in a csv (in Column A) then when it finds it print just the 2nd column (Colum B) not the whole row, this prints both the coloumns in the csv
-------------------

import os

f_name = os.listdir(r'C:\Users\Peter\Documents\Python test\Files')[0]

print(f_name)

import csv

data=[]
with open ("test.csv") as csvfile:
reader = csv.reader(csvfile)
for row in reader:
data.append(row)

col = [x[0] for x in data]

if f_name in col:
for x in range(0,len(data)):
if f_name ==data[x][0]:
action = print(data[x])

else:
print("File not listed")

[perfringo]

Assuming that a file named 'two_columns.txt' contains space separated two columns:

Output:
dummy.txt 7
secret.txt  42
public.txt 123

Then one way of getting desired result could be:

look_for = ('secret.txt', 'public.txt')

with open('two_columns.txt', 'r') as f:
    for row in f:
        first, second = row.split()
        if first in look_for:
            print(second)

# will print:
42
123

[ptey07]

Thanks i will have a play, not sure tho
i have of pictures and a csv the picture file name in column A and location it was taken in Column B
i can get the code to look at the file name then go to the csv and search for the file name and then return the row of data, but i want it to just return the location column of that row. if u get what i mean