How to properly catch this exception

[Emekadavid]

It's better to be specific as to what problem is

while True : 
    score = input('Number between 0 and 1\n')
    try :
        score = float(score)
        if 0 <= score <= 1:
            break
        else:
            print('Number must be between 0 and 1, inclusive. Please try again...') 
    except ValueError:
        print('Not a number. Please try again...')

print(f'You entered: {score}')

Now, if you want to go a step further you can put [part of] this code in a function that takes start and or end argument, ask user for input, validates it and returns the number once correct input.

Thanks. I will implement this suggestion. It's more intuitive.