##### I’m Flat out struggling to understand list indexes
 I’m Flat out struggling to understand list indexes gr3yali3n Silly Frenchman Posts: 34 Threads: 20 Joined: Apr 2020 Reputation: 2 Jul-17-2020, 06:11 AM Let’s say ```x = [0, 1, [2]] x[2][0] = 3 print(x) ```I found this in a book I was scanning through, ok so I’m still trying to understand how this works because it was my understanding that if you used square brackets in this manner the code Would pull from the 3rd item and the 1st element of said item [2][0] but that doesn’t seem to be what is going on here ,How is x[2][0] = 3 coming out to be [0,1,[3]] ? Reply menator01 Minister of Silly Walks Posts: 359 Threads: 53 Joined: Sep 2019 Reputation: 21 Jul-17-2020, 06:22 AM (This post was last modified: Jul-17-2020, 06:22 AM by menator01.) In the fist list 2nd index, first index of inner list the value 3 if you wish to pull and index you do not do an assignment operation ``````Output:>>> x = [0, 1, [2]] >>> x [0, 1, [2]] >>> x[2] [2] >>> x[2][0] 2 >>> x[2][0] = 3 >>> x[2][0] 3`````` Reply Posts: 7,218 Threads: 124 Joined: Sep 2016 Reputation: 549 Jul-17-2020, 07:04 AM `x[2][0] = 3`this is assignment, it does not "access" current value in the list, but assign new value instead If you can't explain it to a six year old, you don't understand it yourself, Albert Einstein How to Ask Questions The Smart Way: link and another link Create MCV example Debug small programs Reply gr3yali3n Silly Frenchman Posts: 34 Threads: 20 Joined: Apr 2020 Reputation: 2 Jul-17-2020, 07:26 PM I mean I realize that this is an assignment to a certain extent but I guess my problem is understanding how does x[2][0] = 3 , what is the first element of [2]? When I play with the code : print([2]) vs print([2][0]) the first prints 2 as a list and the second prints 2 as a int, is this the reason for calling [0] of the [2]? Reply bowlofred Giant Foot Posts: 987 Threads: 3 Joined: Mar 2020 Reputation: 120 Jul-17-2020, 07:42 PM (This post was last modified: Jul-17-2020, 07:43 PM by bowlofred.) x is a list of 3 elements: `[0, 1, [2]]` x[2] is the third element, a list with a single element: `[2]` x[2][0] is the first (and only) element from the previous list: `2` So yes, the first element of [2] is the integer "2". ```>>> l = [2] >>> l[0] 2 >>> l.pop(0) 2``` Reply menator01 Minister of Silly Walks Posts: 359 Threads: 53 Joined: Sep 2019 Reputation: 21 Jul-17-2020, 07:43 PM [0] is the first element of that list. Until it gets reassigned by x[2][0] = 3. Then that element has the value of 3 Reply gr3yali3n Silly Frenchman Posts: 34 Threads: 20 Joined: Apr 2020 Reputation: 2 Jul-17-2020, 08:53 PM (This post was last modified: Jul-17-2020, 08:54 PM by gr3yali3n.) Yes, I see that now, I was playing with idle and it finally hit me, once again my apologies. I’m running on little sleep and constantly chasing a little one around the house, i try to set aside a few hours to study python a day but it usually turns out to be a few minutes here and there to read PDFs ,watch a udemy lecture and practice on my iPhone app. I really want to thank everyone for being so cool here! Reply princetonits Programmer named Tim Posts: 5 Threads: 0 Joined: Jul 2020 Reputation: 0 Jul-20-2020, 07:18 PM Here you can check the visualization for the execution of the code. Step 1: https://prnt.sc/tjvqbj Step 2: http://prntscr.com/tjvqjo Step 3: http://prntscr.com/tjvqok Reply

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