If match not found print last line

[tester_V]

Greetings!
I need to print the last line of a file if a match (second match) not found.
I'm printing all the lines with "match-2" for each "match-1" line.

line-1 match-1
line something else
line something else
line-4 match-2
line-5 match-2
line-6 match-2
line something else
line something else
line something else
line something else
line-11 match-1
line something else
line something else
line-14 match-2
line something else
line something else
line-17 last match-1
line-18 last need to print

Here is the code I got so far:

with open('C:/02/file2.txt','r') as  mf :
    for el in mf :
        el=el.strip()

        if 'match-1' in el :
            one=el.strip()
            #print ("one "+one)
        elif 'match-2' in el :
            tr = el 
            print(one+" , "+tr)     

Code prints :

line-1 match-1 , line-4 match-2
line-1 match-1 , line-5 match-2
line-1 match-1 , line-6 match-2
line-11 match-1 , line-14 match-2

Need also to print :
line-17 last match-1 , line-18 last need to print

Thank you!

[menator01]

Maybe not the best way but might help

#! /usr/bin/env python3
matches = []
with open('file.txt') as file:
    lines = file.readlines()
for line in lines:
    if 'match-1' in line or 'match-2' in line:
        matches.append(line)
        print(line.strip())
if len(matches) % 2 != 0:
    print(lines[-1])

Output:
line-1 match-1
line-4 match-2
line-5 match-2
line-6 match-2
line-11 match-1
line-14 match-2
line-17 last match-1
line-18 last need to print

[tester_V]

I like your thought!
It is great but I need to go with a line-by-line checking the file, it is not a small file and no tone file.
Thank you!