Is there a built-in function to replace multiple bytes?

[Raptor88]

I'm learning Python 3.6.

I figured out how to use the find() function to find a multiple hex byte string in a byte variable as follows:

with open("test 18.vf", "rb") as binaryFile:
    byteData = bytearray(binaryFile.read()) 

mx = 0
while mx != -1:
    mx = byteData.find(b'\x2A\x07\x3B\x1C\x14', mx)
    if mx != -1:
        Do something

Is there a built-in function to change consecutive bytes in "byteData" that looks similar to the find function above?
If not, any suggestions on the easiest way to replace 7 consecutive bytes?  I won't be inserting any bytes.  Just replacing 7 consecutive bytes elsewhere in "byteData".

Thanks.

[Larz60+]

Untested, but this should work:

replace:

   mx = byteData.find(b'\x2A\x07\x3B\x1C\x14', mx)

with:

   bytedata=butedata.replace(b'\x2A\x07\x3B\x1C\x14', b'New value here')

[Raptor88]

Untested, but this should work:

replace:

   mx = byteData.find(b'\x2A\x07\x3B\x1C\x14', mx)

with:

   bytedata=butedata.replace(b'\x2A\x07\x3B\x1C\x14', b'New value here')

Thanks Larz60+.  I won't know the bytes to be replaced as they could vary depending on the user's setup.  I neglected to say that I will be replacing the 7 bytes based on the index value of "mx".

For example:
1. Search for the 5 byte string. 
2. If found, mx = index of first found byte.
3. Add a value to mx to skip bytes.  Like mx += 52.
4. Replace 7 bytes starting from the current index value of mx.
5. Repeat steps 1-4 until the end of "byteData" signified by mx == -1.

Sorry for not being more through in my initial post.
Thanks.

[zivoni]

If you want to replace 7 bytes from given index mx, you can do

byteData[mx : mx+7] = 1, 2, 3, 4, 5, 6, 7

bytearray is mutable, so it will work. And if you want these bytes replaced with different number of bytes, you can use .insert() method or del byteData[index1: index2].

[Raptor88]

If you want to replace 7 bytes from given index mx, you can do

byteData[mx : mx+7] = 1, 2, 3, 4, 5, 6, 7

bytearray is mutable, so it will work. And if you want these bytes replaced with different number of bytes, you can use .insert() method or del byteData[index1: index2].

Hi zivoni,

So simple, so easy, so clean.

Works perfectly, So thanks!
Raptor88