Nested Loop Problem

[GSWes]

New coder here trying to teach himself.

Look closely at the number of "a" in the next sentence. Why does the following code produce "CCCCCttttt" instead of "CCCCCaaaattttt"?

def anti_vowel(text):
t = ""
vowels = "aeiou"
for i in text:
for vowel in vowels:
if i==vowel:
i=""
else:
t = t+i
return t
print anti_vowel("Cat")

[heiner55]

def anti_vowel(text):
  t = ""
  vowels = "aeiou"
  for i in text:
    for vowel in vowels:
        t = t+i
  return t

print( anti_vowel("Cat") )

[Larz60+]

columns are:
1 - Iteration of outer loop
2 - Iteration of inner loop
3 - value of i
4 - value of vowel
5 - value of t

Output:
1        C        
    1    C    a    C
    2    C    e    CC
    3    C    I    CCC
    4    C    o    CCCC
    5    C    u    CCCCC
2        a        
    1    a    a    CCCCCa
    2    a    e    CCCCCaa
    3    a    I    CCCCCaaa
    4    a    o    CCCCCaaaa
    5    a    u    CCCCCaaaaa
3        t        
    1    t    a    CCCCCaaaaat
    2    t    e    CCCCCaaaaatt
    3    t    I    CCCCCaaaaattt
    4    t    o    CCCCCaaaaatttt
    5    t    u    CCCCCaaaaattttt

[heiner55]

Thanks. Nice output.

[GSWes]

I still don't know why the code produced no "a." I thought it would produce 4 "a."

def anti_vowel(text):
   t = ""
   vowels = "aeiou"
   for i in text:
      for vowel in vowels:
         if i==vowel:
            i=""
         else:
            t = t+i
      return t

print anti_vowel("Cat")

---

The inner loop seems to be stopping as soon as if i == vowel is satisfied. Why doesn't it keep looping until it goes through vowel in vowels?

[Larz60+]

You're never using vowel after extracting it.
and 'a' is being printed (with 'Cat' passed to function).
see my output.
so where you say:

      for vowel in vowels:

you could have used

for x in range(5)

and got the same output