needed str around a file pathname to open it

[adetheheat]

I obtained a file pathname ending with .lst in the root dir like this:

for file_path in Path(args.path).glob('**/*.lst'):

and I wanted to open the file file_path but needed str(file_path) to do so:

for codeline in open(str(file_path)):

why did I need the 'str' call ? I thought file_path was a string anyway ?
Is there a way of doing this without the 'str' call as it seems strange I needed it ?
Thanks

[DeaD_EyE]

Older Python versions are not everywhere compatible with Path objects. What you see is just the str representation, but it is not a str object. Never versions of Python can handle Path objects in stdlib and builtins. Instead you could also use the Method open of the Path object.

with Path("file.ext").open() as fd:
     for line in fd:
         ...

Tje Path object has also the methods read_text() and read_bytes().