PYTHON AND JSON >please correct this corde

[just_started_python]

 JSON file that contains the following pieces of information:

• Database Connection Information:
  
  • Database User Name
    
  • Database Password
    
  • Database Host
    
  • Database Name
    
  
  
• Start Date - The start date for data to process, in the format YYYY-MM-DD
  
• End Date - The end date for data to process, in the format YYYY-MM-DD
  
• Cost Field Mapping - This is a dictionary that contains entries that describe which fields should be summed to compute an output field, total cost
  

My answer 

import json
def setup(filename):
    """(str) -> dict
    The function reads from the specified configuration file, in JSON format, and stores the contents
    in a Python dictionary.  That dictionary is returned to the caller, as shown in #4.
    
    >>> setup('/final/config_sample.json').get("Database User")
    'slucor'
    
    >>> setup('/final/config_sample.json').get("Cost Field Mapping")["MG001"][0]
    'ingredient_cost'
    
    >>> setup('/final/config_sample.json').get("Cost Field Mapping").get("AZ001")[1]
    'admin_fee'
    """

with open (filename, "r") as inputFile:
    data=inputFile.read().replace('\n', '')
return json.loads(data)

print(setup('config_sample.json').get("Database User"))
print(setup('config_sample.json').get("Cost Field Mapping")["00400F"][0])
print(setup('config_sample.json').get("Cost Field Mapping").get("00670H")[1])

Please help me correc it . ITs not working

[nilamo]

Please help me correc it . ITs not working

In what way is it not working?  Is there an error?  What's the error?

[just_started_python]

its saying that '(filename)' not defined

[nilamo]

You mean the with block?  Where you try to open a file using the variable filename as the file to open?  Try defining it then :p