Parsing file and get a specific text

[dds69]

Hi everyone,

I'm new in scripting with python (in general too). I need some help to get a block text in a file.

This is my code :

stop = "end"
last_line = 0
searchtxtDetected = False
with open("20181107-115829-192.168.220.201.txt", 'r') as file:
	for txt in file:
		if 'show running-config' in txt:
			searchtxtDetected = True
			continue
		if searchtxtDetected:
			print (txt)
			#last_line += 1
			if txt == stop:
				break

Nevertheless, the code start when show running-config is parse but dont stop when it match my variable and print the entire file end !

The file to check my code
https://ufile.io/4eiaa

[ichabod801]

When you loop through the lines in a file like that, you will have a newline character at the end of each line. Try changing the last comparison to if txt.strip() == stop:, or setting stop = 'end\n'.

Also, file is a built-in type in Python. If you use it as a variable name, it might mess up other code that depends on it.

[Gribouillis]

Use stop = "end\n"

[woooee]

And reverse the two if statements to get rid of the continue

    for txt in file:
        if searchtxtDetected:
            print (txt)
            #last_line += 1
            if txt == stop:
                break
        if 'show running-config' in txt:
            searchtxtDetected = True

Also, a break and/or continue statement is unreliable IMHO for nested loops. Especially if the code is modified in the future and someone adds another nested loop. It is better to use a function, and return from the function instead of the break.

[dds69]

Hi,

Thanks for your replies !

I've tested your solution and the result is ok for the entire solutions :D

I'm going care about your advices and making better my code.

Thanks you everyone.

dds69