Problem with assigning directory of a file based on cell name

[mmaz67]

Hi, I wanted to create a script that can opened a text file, c_name.txt where the content of the text file would be list of cell names. After i opened, i need to assign all the cell names as a variable. This is because i need the cell name to open up the next directory which requires the cell name.

#!/usr/bin/python

import os
import os.path

myPWD = os.getcwd()
workspace = "%s/.." %(myPWD)
os.chdir(myPWD)

floc = '/'.join([myPWD, "c_name.txt"])

with open(floc, "r+") as f1:
    cell_names = f1.readlines()

for cell_name in cell_names:
    floc2 = '/'.join([workspace, "library", "ce_ll or ce_ls", "{0}.rpt".format(cell_name)])
    with open(floc2, "r+") as f2:
        for line in f2:
                print line

For floc2, I need to classify if cell name starts with ce_ll, then the report files will be in ce_ls directory whereas if the cell name starts with cell, then the report files will be in cell directory.

Here how it looks like in c_name.txt:
ce_ll_sum
ce_ls_sub
ce_ll_add
ce_ls_clk

Besides, the script located in workspace/test/c_name.txt while the report file is located in workspace/library/$ce_ll or $ce_ls/cell.rpt

[Larz60+]

something like:

>>> filelist = []
>>> with open('c_name.txt') as fp:                   
...     for line in fp:                              
...         filelist.append(line.strip())            
...                                                  
>>> filelist                                         
['ce_ll_sum', 'ce_ls_sub', 'ce_ll_add', 'ce_ls_clk'] 
>>>                                                  

[mmaz67]

But the problem is, the list of cells in c_name.txt is not just 4, it could be up to 50 cell name and may differ time to time. Is there any way to make it more generic?

[Larz60+]

But the problem is, the list of cells in c_name.txt is not just 4, it could be up to 50 cell name and may differ time to time. Is there any way to make it more generic?

Just replace the list (unless you need it for some other purpose, with running each file in loop, then,
50, 1000, why does it matter. If in a list, it's a simple iteration, in fact a list is not needed:

import os


# Assure in proper directory
os.chdir(os.path.dirname(__file__))

def process_files():
    filelist = []

    with open('c_name.txt') as fp:
        for line in fp:
            pass
            # replace pass with your code for each file here


if __name__ == '__main__':
    process_files()

The added code just makes sure that the source directory is cwd (which is where this script expects data file) you can change that to whatever data directory you wishm but keep it relative to the source.