Program: count and find

[Truman]

# [ ] find and report (print) number of w's, o's + use of word "code"
work_tip = "Good code is commented code"

# [ ] count times letter "i" appears in code_tip string
# [ ] find and display the index of all the letter i's in code_tip
# Remember: if .find("i") has No Match, -1 is returned
code_tip = "code a conditional decision like you would say it"
print ("code_tip:" , code_tip)

my code:

code_tip = "code a conditional decision like you would say it"
a = code_tip.count("w")
b = code_tip.count("o")
c = code_tip.count("code")
print(a)
print(b)
print(c)
cnt = code_tip.count("i")
print(cnt)
ind = code_tip.find("i")
for i in code_tip:
    if code_tip.find("i"):
        print(ind)
        break
    else:
        print("not found")
print ("code_tip:" , code_tip)

I have a problem with bolded task. Don't know how to print indexes for all six i's. Help is appreciated.

[Larz60+]

To get index,

print(code_tip.index('i'))

you can then use slice
see: http://www.pythonforbeginners.com/dictio...on-slicing

[Truman]

Larz, this code gives output 6. My understanding of the task is that I should find a way to print all indexes, for each 'i'.
By the way, I know about slicing.

[Larz60+]

That's why I included:

you can then use slice
see: http://www.pythonforbeginners.com/dictio...on-slicing

Your prof probably wants you to use slice. Get index, slice at index, get next index, appending results to list.
If allowed, you can also use list comprehension
list_of_i = [i for i, x in enumerate(code_tip) if x == 'i']

>>> code_tip = "code a conditional decision like you would say it"
>>> list_of_i = [i for i, x in enumerate(code_tip) if x == 'i']
>>> list_of_i
[11, 13, 22, 24, 29, 47]
>>>

If you turn this in, better be able to explain what's going on.
I suggest reading up on slices and going about it that way