Replacing string values with count

[tomhuang]

my question here

Define a function that takes a string and replaces each character with a string of the number of times that letter occurs in the word.
'Hello' -> '11221'
Ignore capitalization, so if a word has an 'H' and an 'h' the count would be more than 1.

import collections
a = 'Hello'
letters = collections.Counter(a.lower())

dict(letters)

[wavic]

So get the string and for each letter get the value from the dict. Then join all values in a new string.

[nilamo]

my question here

Define a function that takes a string and replaces each character with a string of the number of times that letter occurs in the word.
'Hello' -> '11221'
Ignore capitalization, so if a word has an 'H' and an 'h' the count would be more than 1.

import collections
a = 'Hello'
letters = collections.Counter(a.lower())

dict(letters)

Looks like you've got it.  So what's the problem?

If you don't want to use a module, you can always roll your own:

>>> val = "Hello"
>>> "".join(map(str, map(sum, ((1 for ch in val if ch.lower()==pos.lower()) for pos in val))))
'11221'