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 Select single letters from string based on separate string Jpen10 Programmer named Tim Posts: 9 Threads: 3 Joined: Dec 2019 Reputation: 0 Likes received: 0 #1 Dec-10-2019, 03:10 PM I've done this in Excel using the =Lookup({}) function, but have no clue how to in Python. String 1 (12 digits): 085236752048. String 2 (10 letters): @ABCDEFGHI. I need to select 5 letters from string 2, based on the values of string 1 from the 7th-11th digit. In this case the result would be; GEB@D. I've tried slice(), but found that I can't index a slice. Thanks for any help. (this is not critical.) ibreeden Not Blown Up Yet Posts: 61 Threads: 0 Joined: Aug 2019 Reputation: 7 Likes received: 6 #2 Dec-10-2019, 07:55 PM You are asking complicated things. Are you inventing a new encryption mechanism? You may solve it in this way: ```s1 = '085236752048' s2 = '@ABCDEFGHI' print(''.join(s2[int(ch)] for ch in s1[6:11])) `````````Output: GEB@D ``````Explanation: `for ch in s1[6:11]`: Walk through the numbers in string 1 (mind you: index starts at 0 and last index is not included) `s2[int(ch)]`: make an integer of the character found in the loop and consider this as an index in string 2. `''.join(...)`: start with an empty string and join this successively with the characters found. Jpen10 Programmer named Tim Posts: 9 Threads: 3 Joined: Dec 2019 Reputation: 0 Likes received: 0 #3 Dec-11-2019, 01:04 AM I Breeden, Thank you very much. I have a font that is specific to UPCA. the bars are set for consecutive letters and a couple of symbols. The solution you provided gave me the necessary code to equate the two. I can now enter the 11 numbers and it will figure the check Digit, then it converts the entire 12 digits to the font readable text for a UPCA symbol. I added, with your code, the first number, the next 5 numbers, the separator, the last five (your code) and the check Digit. I've worked on this ever since since I coded a program in 1983 in Basic and QBasic. I moved on to Excel and then to Microsoft Access, both with macros in Visual Basic. The program won't produce a scanner readable UPCA symbol. Again my thanks. Jim Jpen10 Programmer named Tim Posts: 9 Threads: 3 Joined: Dec 2019 Reputation: 0 Likes received: 0 #4 Dec-15-2019, 01:21 PM Ibreeden, A couple of days ago I finally achieved a scanner readable label with win10,Spyder,Tkinter. « Next Oldest | Next Newest »

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