Syntax error for code that seems correct

[mcnhscc39]

I'm pretty new to programming and Python so there may be other issues with my code here. The error is in line 8 of the code.

I keep getting a syntax error on the = and if I delete that I get it on the <. I've crossed referenced with my Python book but it looks good. Any ideas as to what the issue is?

#Display message
print("Shipping Calculator")

#Get data
choice = "y"
while choice.lower() == "y":
    cost = float(input("Cost of items ordered: "))
    if cost  >= 0 and <= 30.00:
        shipping = float(5.95)
        print("Shipping cost      " + str(shipping))
    elif cost <= 49.99:
        shipping = float(7.95)
        print("Shipping cost:     " + str(shipping))
    elif cost <= 74.99:
        shipping = float(9.95)
        print("Shipping cost:     " + str(shipping))
    elif cost > 74.99:
        shipping = float(0)
        print("Shipping cost:     " + str(shipping))
    elif cost < 0:
        print("Error! Please enter a positive number and try again. ")
    total = cost + shipping
    print("Total Cost:        " + str(total))
    #Get user choice
    choice = input("Would you like another calculation? y/n: ")

#Display Bye
print("Bye!")

[j.crater]

There's a value missing to compare to

if cost  >= 0 and cost <= 30.00

better yet:

if cost 0 <= cost <= 30.00

[mcnhscc39]

There's a value missing to compare to

if cost  >= 0 and cost <= 30.00

better yet:

if cost 0 <= cost <= 30.00

The first suggestion worked, but for some reason the second one did not. Either way it fixed my problem as I was overlooking the value. Oddly enough, in the Murach Python book I have it was missing the value as well. I had to adjust some other lines to ensure that the user received an error message for a negative number but it's running as intended now. Thank you.

[nilamo]

if cost 0 <= cost <= 30.00

Get rid of the first cost:

if 0 <= cost <= 30.00:

[j.crater]

That was clumsy copy-pasting, sorry. And thanks for pointing the typo out nilamo.