Translator

[Zatoichi]

def load_dictionary(filename):
    
    dictionary = {}
    with open('Hmong.txt', 'r') as input_file:
        for lines in input_file:
            info = lines.strip('\n').split(',')

            dictionary[info[2]] = info[1]
    return dictionary

def user_input():
    sentence = input('Type your English sentence:')
    return sentence
     
def translate(sentence, dictionary):
    words = sentence.split()
    for word in words:
        
        if word in dictionary:
            print (dictionary[word], sep=' ', end=' ')
        
        else:
            print('?') # Unknown word
        
        
def print_word_frequency(sentence):    
    counters = {}
    words = sentence.split()
    
    for word in words:
        
        if word not in counters:
            counters [word] = 1 #First occurrence of a word starts counter
        else:
            counters [word] += 1 #if repeat word add to existing counter
    print ('Word' + ' ' + 'Frequency')
    for word, count in counters.items():
        
        print (word, count)


def main():
    dictionary = load_dictionary('Hmong.txt')
    sentence = user_input()
    translate(sentence, dictionary)
    done = False
    while not done:
        print()
        another_translation = input('Another translation (Y/N):')
        if another_translation == 'Y' or another_translation == 'y':
            main()
        elif another_translation == 'N' or another_translation == 'n':
            print_word_frequency(sentence)
            done = True
    
    
    
main()

So I pretty much got my code finished but I have ran into a few issues. I need to integrate my counter in another way so it keeps track of all words typed not just the last one. Because I have been ending up with this.

Output:
Type your English sentence:I can help
kuv tau pab 
Another translation (Y/N):y
Type your English sentence:no can help
tsis muaj tau pab 
Another translation (Y/N):n
Word Frequency
no 1
can 1
help 1

and also I can not for the life of me figure out how to align the numbers from the count under the F in frequency.

[Larz60+]

Here's how to count and align:

sentence = 'This is a random sentence, if a random sentence is what you want'
slist = sentence.split()
counts = {i:slist.count(i) for i in slist}
for key, value in counts.items():
    print('{:>10} {:>10}'.format(key, value))

results:

Output:
      This          1
        is          2
         a          2
    random          2
 sentence,          1
        if          1
  sentence          1
      what          1
       you          1
      want          1

Or for left aligned text:

sentence = 'This is a random sentence, if a random sentence is what you want'
slist = sentence.split()
counts = {i:slist.count(i) for i in slist}
for key, value in counts.items():
    print('{:<10} {:<10}'.format(key, value))

Output:
This       1         
is         2         
a          2         
random     2         
sentence,  1         
if         1         
sentence   1         
what       1         
you        1         
want       1         

[Zatoichi]

will that counting method keep track of all words entered in each input though? and not just the last input the user did before they quit the program.

[Larz60+]

No, you have to accumulate

[Zatoichi]

How do I go about doing that? Making a global counter?

[Larz60+]

You have to do it a bit differently if you want to accumulate:

counts = {}

def add_sentence(sentence):
    slist = sentence.split()
    for word in slist:
        word = word.strip()
        if word in counts:
            counts[word] += 1
        else:
            counts[word] = 1

def print_counts():
    for key, value in counts.items():
        print('{:<10} {:<10}'.format(key, value))
    print('\n-------------------\n')

def main():
    sentence1 = 'This is a random sentence, if a random sentence is what you want'
    sentence2 = 'This is another sentence like the first'
    add_sentence(sentence1)
    print_counts()
    add_sentence(sentence2)
    print_counts()
main()

result:

Output:
This       1         
is         2         
a          2         
random     2         
sentence,  1         
if         1         
sentence   1         
what       1         
you        1         
want       1         

-------------------

This       2         
is         3         
a          2         
random     2         
sentence,  1         
if         1         
sentence   2         
what       1         
you        1         
want       1         
another    1         
like       1         
the        1         
first      1         

-------------------

[Zatoichi]

That works okay if I know how many times the user will use the translation before quitting but if I have no idea it really does not work. I guess I will have to keep searching how to do it.

[Larz60+]

Please, you should be able to figure out how to do that.
It's quite simple, all the work is done!

[Larz60+]

loop...
while not quit
input sentence
call add_sentence
...
call print_counts

[Zatoichi]

Sorry, my fault for not realizing it sooner. Thanks!

---

counts = {}


def load_dictionary(filename):  #load the dictionary text file English to Hmong
    
    dictionary = {}
    with open('Hmong.txt', 'r') as input_file:
        for lines in input_file:
            info = lines.strip('\n').split(',')

            dictionary[info[2]] = info[1]
    return dictionary

def user_input(): #Get the user sentence in English that needs to be translated
    
    sentence = input('Type your English sentence:')
     
    return sentence
     
def translate(sentence, dictionary): #take the user inputted sentence and split it into indvidual words and then translate each word
    words = sentence.split()
    
    for word in words:
                
        if word in dictionary:
            print (dictionary[word], sep=' ', end=' ')
                   
        else:
            print('?',end=' ') # Unknown word
   
def add_sentence(sentence): #take the user sentence and split and count each word 
    words = sentence.split()
    for word in words:
        word = word.strip()
        if word in counts:
            counts[word] += 1 # if word already in count it adds another count to it
        else:
            counts[word] = 1  # if word not in count creates new count for the word
     
def print_word_frequency():    #once user quits prints the words and frequency of the words

    print ('{:<10} {:<10}'.format ('Word','Frequency'))
    print('-------------------')
    for key, value in counts.items():
        print('{:<10} {:<10}'.format(key, value))    


def main(): #main function to call upon the other functions so they work together
    dictionary = load_dictionary('Hmong.txt')
    sentence = user_input()
    translate(sentence, dictionary)
    add_sentence(sentence)
    done = False
    while not done:
        print()
        another_translation = input('Another translation (Y/N):')
        if another_translation == 'Y' or another_translation == 'y':
            main()
        elif another_translation == 'N' or another_translation == 'n':
            done = True
            print_word_frequency()
            
    
    
    
main()

I do not suppose you could tell me why my code asks for another translation after saying not if I do it after more then one attempt.

Output:
Type your English sentence:I can help
kuv tau pab 
Another translation (Y/N):I can help you help him

Another translation (Y/N):y
Type your English sentence:I can help you help him
kuv tau pab koj pab nws 
Another translation (Y/N):n
Word       Frequency 
-------------------
I          2         
can        2         
help       3         
you        1         
him        1         

Another translation (Y/N):

and when there is only one entry it quits as it should.

Output:
Type your English sentence:I can help you help him
kuv tau pab koj pab nws 
Another translation (Y/N):n
Word       Frequency 
-------------------
I          1         
can        1         
help       2         
you        1         
him        1