TypeError: '<=' not supported between instances of 'list' and 'int'

[Leonzxd]

#Print A Simple Payroll Report
name = ['Hai', 'Bell', 'Cindy', 'Danny', 'Eddy', 'Felicia', 'Gigi', 'Apple','Indie','Jacon','Kim','Lim']
hours = [10, 45, 60, 70, 20, 35, 80, 30, 65, 55, 15, 90]
rate = 9.5


n = len(name)

print('\n\t    Payroll Report\n')
print('No.\tEmployee Name\tHours\tSalary(RM)')

for i in range(n):
    if hours <= 40:
        wage = hours*rate
    elif  hours <= 60:
        wage = 380 + (hours + 40) * rate * 1.5
    else:
        665 + (hours + 60) * rate * 2.0
        

    print('%d\t%s\t%d\t%s' % (i+1, name[i], hours[i], wage))

---

Why is it not supported?
Or did I miss something?

[wavic]

Line 13.
You cannot compare a sequence against an integer.
Same for the elif statement.

[Leonzxd]

I forgot to mention
I was thinking to make an Output like this:

No. Employee Name Hours Salary(RM)
1 XXX 10 75
2 CCC 45 356.25
3 Bell 65 675

[ThiefOfTime]

When I understand your code correctly, you want to compare the hours of one person with 40(60), so you need the hours at the position of i, so

if hours[i] <= 40:
        wage = hours*rate

[Leonzxd]

When I understand your code correctly, you want to compare the hours of one person with 40(60), so you need the hours at the position of i, so

if hours[i] <= 40: wage = hours*rate

Yessss!
Thanks, sorry forgot to reply.