Why is this the output I am getting?

[wlsa]

def func_a():
    print('inside func_a')
def func_c(z):
    print('inside func_c')
    return z()
print(func_c(func_a))

the output I get is
inside func_c
inside func_a
None

I'm having a hard time understanding how putting a function as an input into another function gives me this output.

[ichabod801]

You pass func_a to func_c without calling it. func_c prints, and then calls the function that was passed to it (z()). So that calls func_a, which prints. func_a returns None (the default return value) to func_c, which does nothing. func_c returns None to the print function on line 6, and it gets printed.