int format for 001 - 999

[jmair]

Is there a build it method to do the following?

num = 001

num += 1

print(str(num))

result: 002

currently I get an 'Invalid token' error with 001 as a variable

I'm just looking for a way to count 001, 002 - 999. Rather not reinvent the wheel if something already exists.

Thanks!

[nilamo]

Numbers with leading zeros are illegal, because doesn't want you to get confused about whether or not they're octal numbers (which are, instead, defined with a leading 0o in python). If you remove the leading zeros, your code will work fine.

[snippsat]

I'm just looking for a way to count 001, 002 - 999.

Use string formatting f-string is what you should use need 3.6+,version before that use format().

for i in range(1,21):
    print(f"{i:03}") 

Output:
001
002
003
004
005
006
007
008
009
010
011
012
013
014
015
016
017
018
019
020

[scidam]

Sometimes, e.g. when it is needed to create/(or load) numbered files, you need to create strings
such as '001', '002' etc. To get this you could use .format method, e.g.

"{:03d}".format(4)

Output:
'004'

========
P.S.
Too late, the same answer already exists...

[jmair]

That's exactly what I needed! Thank you!