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 comparing each rows of two matrix Gribouillis Posts: 1,571 Threads: 12 Joined: Jan 2018 Reputation: 146 Likes received: 375 #11 May-17-2019, 06:50 AM (This post was last modified: May-17-2019, 06:50 AM by Gribouillis. Edited 1 time in total.) Here is how you could print every pair of identical rows ```from collections import defaultdict import itertools as itt import numpy as np a=np.matrix([[1,2,3],[42,68,69],[1,2,3],[85,89,95]]) b=np.matrix([[42,68,69],[1,2,3],[85,89,95], [42,68,69]]) def group_lines(m): d = defaultdict(list) for i, row in enumerate(m.A): d[tuple(row)].append(i) return d def identical_rows(ma, mb): da, db = (group_lines(m) for m in (ma, mb)) for row, na in da.items(): if row in db: yield from itt.product(na, db[row]) if __name__ == '__main__': for i, j in identical_rows(a, b): print(i, j, a.A[i]) ```The result is``````Output:3 2 [85 89 95] 1 0 [42 68 69] 1 3 [42 68 69] 0 1 [1 2 3] 2 1 [1 2 3] `````` PhysChem likes this post « Next Oldest | Next Newest »

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