container data type formatting

[nzcan]

hello,

one interesting task:

>>> gaga(15)
[ 1, 2, 'gaga', 4, 'bieber', 'gaga', 7, 8, 'gaga', 'bieber', 11, 'gaga', 13, 14, 'gagabieber' ]

until now i have managed to:

 
def gaga(n):
    n = list(range(1, n + 1))
    s = ['gaga' if cm % 3 == 0 else cm for cm in n]
    return s
 

def gaga(n) -> gabi.py
it works in the interactive mode of the interpreter:

>>> import gabi
gabi.gaga(15)
[1, 2, 'gaga', 4, 5, 'gaga', 7, 8, 'gaga', 10, 11, 'gaga', 13, 14, 'gaga']

then i try in some unfolded form:

def gaga(n):
    n = list(range(1, n + 1))
    for cm in n:
        
        if cm % 3 == 0:
            cm % ('gaga')

        elif cm % 5 == 0:
            cm % ('gagabieber')

    print(cm) 

but it does not work. some ideas?
thanks in advance!

[buran]

if it is divisible by 3 - print gaga
if it is divisible by 5 - print bieber
if it is divisible by both 3 and 5 - print gagabieber
I will leave to you, how to check and in what order

[Gribouillis]

            cm % ('gaga')

What is the result of 3 % ('gaga') ?

[nzcan]

hi,
i have found one solution of the fizzbuz task that works good.

def fb(n):
	
	n = list(range(1, n +1))
	
	for cm in n:

		if cm % 3 == 0 and cm % 5 == 0:
			print('fizzbuz')
		elif cm % 3 == 0:
			print('fizz')
		elif cm % 5 == 0:
			print('buzz')
		else:
			print(cm)

this solution saved in a fizz_t.py file can be imported in to the interactive mode of the interpreter
and after we call it, it will return a for-loop iteration:

>>> import fizz_t
>>> fizz_t.fb(16)
1
2
fizz
4
buzz
fizz
7
8
fizz
buzz
11
fizz
13
14
fizzbuz
16
>>> 

how the fb-function should look like if we want that it returns not a for-loop iteration, but a list like in:

>>> fizz_t.fb(15)
[ 1, 2, 'fizz', 4, 'buzz', 'fizz', 7, 8, 'fizz', 'buzz', 11, 'fizz', 13, 14, 'fizzbuzz' ]

thanks in advance

[nzcan]

i found the solution of this task, but it is pretty unexpected and complicated!

[Gribouillis]

Here is a version with two functions

def gabize(n, a, b):
    if n % 15 == 0:
        return a + b
    elif n % 3 == 0:
        return a
    elif n % 5 == 0:
        return b
    else:
        return n
    
def func(n, a='gaga', b='bieber'):
    return [gabize(i, a, b) for i in range(1, n + 1)]

if __name__ == '__main__':
    print(func(15))
    print(func(15, 'fizz', 'buzz'))

Output:
[1, 2, 'gaga', 4, 'bieber', 'gaga', 7, 8, 'gaga', 'bieber', 11, 'gaga', 13, 14, 'gagabieber']
[1, 2, 'fizz', 4, 'buzz', 'fizz', 7, 8, 'fizz', 'buzz', 11, 'fizz', 13, 14, 'fizzbuzz']