create function let_to_num()

[Truman]

let_to_num() takes input of a single letter, space or empty string stored in an argument variable: letter
use while key < 10: to try numbers 0 - 9 as index for phone_letters ("key" = phone dial pad key)
check if letter variable is in the index of phone_letters[key]

key = 0
while key < 10:
if # Create Code: determine if letter is **in** any of the phone_letters[key] where key is the index 0 -9:
return key
else:
key = key + 1
return "Not Found"

return the number or "Not Found"
call let_to_num() to test the function so it prints the argument and return value with:
space
lowercase letter
different letter, uppercase
a number

my code:

phone_letters = [' ', '', 'ABC', 'DEF', 'GHI', 'JKL', 'MNO', 'PQRS', 'TUV', 'WXYZ']
def let_to_num(letter):
    letter=input("Enter single letter, space or empty: ")
    key = 0
    while key < 10:
        for letter in phone_letters:
            if l in letter:
                return (phone_letters.index(letter))
            else:
                key = key + 1
        else:
            print("Not found")
print(let_to_num(letter))
            

Whatever character that I add it prints 9. I'm not sure that I even understand the task, your opinion is appreciated.

[ka06059]

lets assume no semantic error....

phone_letters = [' ', '', 'ABC', 'DEF', 'GHI', 'JKL', 'MNO', 'PQRS', 'TUV', 'WXYZ']
def let_to_num():  #letter argument removed, input() will do the job
    letter=input("Enter single letter, space or empty: ")
    key = 0
    while key < 10: # 'for letter in phone_letters' loop not needed, this line will loop along phone_letters anyway
        if letter in phone_letters[key]:
                return key  #key is the index itself
        else:
            key = key + 1
    return ("Not found") #should return 'not found' instead, it will be printed in line 11
print(let_to_num())

Output:
Enter single letter, space or empty: D
3
Enter single letter, space or empty: Q
7

check out the comment lines for few explanations