data from multiple Entry widgets

[beevee]

Hi, New python user here.

I have an array of 160 Entry widgets. I created them inside nested for loops, rather than 160 explicit lines. Now, I don't know how to read them. I tried:
(Inside FOR loops)

xxx[a,b,c] = Entry(root, bg="white",fg="black", width=7, relief=SUNKEN).grid(row=p_row,column=p_col+1)

I then tried getting the data like this:

for a in range(8):
          for b in range(4):
            for c in range(5):
               xxx[a,b,c].get()
    print(xxx)

But it doesn't work. Is there a way to do this, or do I have to have 160 lines with 160 separate variables?

Thanks,

[bowlofred]

What do you expect line 4 to do? If any data is returned by the get(), it's immediately discarded because you don't assign it to anything. So the sub loops don't do anything useful.

[deanhystad]

Get 1 entry to work before you make 160.

This is not going to work the way you want. Why is x None?

xxx = Entry(root).grid(row=0,column=0)
print(x)

[beevee]

What do you expect line 4 to do? If any data is returned by the get(), it's immediately discarded because you don't assign it to anything. So the sub loops don't do anything useful.

I EXPECT line 4 to read the data from the associated entry and put it in an array. If a=1 and b=2 and c=3, I expect array element xxx[1,2,3] to be assigned the value from the Entry widget previously assigned in the for loop:

xxx[a,b,c]=Entry(...

[deanhystad]

xxx = Entry(root).grid(row=0,column=0)

Entry(root) creates an entry object. What does .grid do? What is returned when you call Entry(root)? What is returned when you call .grid?

Don't EXPECT. VERIFY.

[beevee]

xxx = Entry(root).grid(row=0,column=0)

Entry(root) creates an entry object. What does .grid do? What is returned when you call Entry(root)? What is returned when you call .grid?

Don't EXPECT. VERIFY.

Don't lecture me. Your condescending attitude is offensive.

I'm trying to verify it. THAT'S WHY I POSTED THIS!

.grid positions the widget.

[deanhystad]

xxx = Entry(root).grid(row=0,column=0)

Entry(root) creates an entry object. What does .grid do? What is returned when you call Entry(root)? What is returned when you call .grid? When I look at the documentation see that .grid does position the widget and it RETURNS NONE. So you are starting you program by throwing away any handle you have to the Entry objects.

Later on you make another mistake, but you should probably get your list of Entry widgets working first.

Don't EXPECT. VERIFY.

Don't lecture me. Your condescending attitude is offensive.

I'm trying to verify it. THAT'S WHY I POSTED THIS!

.grid positions the widget.

Not lecturing. If you lookup what .grid does you will have the answer to your question.

[bowlofred]

I EXPECT line 4 to read the data from the associated entry and put it in an array.

I don't know what list/array you want it to be put in. Something like

mylist.append(xxx[a,b,c])

would put the value onto mylist. In the original line, there's no location for the data that you're looking up.

[beevee]

I EXPECT line 4 to read the data from the associated entry and put it in an array.

I don't know what list/array you want it to be put in. Something like

mylist.append(xxx[a,b,c])

would put the value onto mylist. In the original line, there's no location for the data that you're looking up.

This is where my confusion is coming from. Let me be more specific:
1) I want to create 160 Entry widgets on the screen
2) I want a function to read the data in those 160 widgets.

The way I understand it, I could create 160 discrete Entry widgets like this:

 e1=Entry(...
e2=Entry(...
e160=Entry(...

Then to read the data I could write:

 xxx[0,0,0]=e1.get()
xxx[0,0,1]=e2.get()
xxx[7,4,3]=e160.get()

Am I correct so far?

So, I want to condense like I could in, say, C, using for loops so that I don't have to write 320 lines.

[deanhystad]

The array is not the problem. If you did this

xxx[a,b,c] = Entry(root....)
xxx[a,b,c].grid(...

You would have a list of entry widgets that you could later use like this:

values[a,b,c] = xxx[a,b,c].get()

The problem you were having had to do with not knowing that .grid returns None and not saving the values returned by get(). You would have the same problem if you used independent variables.