find a string in multiple files and display the output

[chiluvur9]

I have tried to search a string from a file and it worked.

>>> if 'finish' in open('/home/user/python/drsync-test-aix.log').read():
...     print "true"
...
true

But I am unable to find how to search the same string in multiple files that end with .log extension, can someone help me

[Larz60+]

You need to

• create an empty list
  
• Create a loop
  
• open each file
  
• test for 'finish'
  
• if you find it, append filename to list
  

[wavic]

Hello!

You can run through a directory:

For both:

import glob
import os.path
import os

# for a single directory
for file in glob.glob('/path/*.log'):
    files_list.append(os.path.abspath(file)

or the directory tree

for root, dirs, files in os.walk("path"):
    if files:
        for file in files:
            if os.path.splitext(file) == '.log':
                files_list.append(os.path.abspath(file))

and search for such a files. For every file get the absolute path and store all these paths for files in a list. Then can open files from the list with a for loop.

[chiluvur9]

Thanks wavic it worked, how mail the below output

>>> for file in glob.glob('/path/*.log'):
...     if 'Finish' in open(file).read():
...             s2=file.split('-')[1]
...             print s2, " DR sync is successful"
...     else:
...             s2=file.split('-')[1]
...             print s2, " DR sync is failed"
...

Output:
A2D  DR sync is successful
B2D  DR sync is successful
C2D  DR sync is failed

Edit admin use code tag

[wavic]

Don't know. Never done it myself.
See smtplib

It may work but see os.path and glob modules and what can you do with them. Learning is essential