find max() value

[perfringo]

This code can't be functional. It should give you NameError on row #12. There is no 'i' to split.

[tuxandrew]

Maybe because the items in list_highest are strings and not integers.

Yes, Thank you.
Is there any other methods to access those lists and print it using max() inside the loop?
Any help would be appreciated.

Let me share more info.

###########################################################
The values from “testname.txt” has been appended to the following lists.

“testname.txt” adde below.

name sub1 sub2 sub3 sub4
mark 20 50 40 20
teo 40 60 60 50
jain 60 70 70 60
lue 80 40 80 30
hed 40 30 30 40

The code is formatted and pasted below.

f = open ( "testname.txt" , "r" )
list1 = [ 20 , 40 , 60 , 80 , 40 ]
list2 = [ 50 , 60 , 70 , 40 , 30 ]
list3 = [ 40 , 60 , 70 , 80 , 30 ]
list4 = [ 20 , 50 , 60 , 70 , 40 ]
r = 0
for j in f:
    if r = = 0 :
        r = 1
        k = j.split()   #'i' was typo
        list_names = [] #will hold the list names
        list_names.append(k[ 1 ])
        list_names.append(k[ 2 ])
        list_names.append(k[ 3 ])
        list_names.append(k[ 4 ])
    else :
        w = j.split()
        list_highest = []
        list_highest.append(w[ 1 ])
        list_highest.append(w[ 2 ])
        list_highest.append(w[ 3 ])
        list_highest.append(w[ 4 ])
        print ( "The highest values of" ,list_names[j], "=" , max (list_highest))  #, max(list_highest)) ==> is not working

Q: with respective to this code above, Is there any ways to print the max() elements in the loop.
##############################################################################

[perfringo]

Maybe I don't fully understand the problem. I assume that objective is to print rows integers maximum value. One can just:

with open('testname.txt', 'r') as f:
    header = next(f)
    for row in f:
        data = row.split()
        print(f"Maximum value on {data[0]}'s row is {max(data[1:], key=lambda x: int(x))}")

If row number instead of name needed one can use enumerate and start at appropriate number (is header row #1?).

This code will output:

Output:
Maximum value on mark's row is 50
Maximum value on teo's row is 60
Maximum value on jain's row is 70
Maximum value on lue's row is 80
Maximum value on hed's row is 40

EDIT:
It is also possible to split and assign names in one go. If appropriate names are used it can deliver better readability. Also no need for lambda, int can be called directly.

name, *values = row.split()      # name is string and values is list
print(f"Maximum value on {name}'s row is {max(values, key=int)}")

[tuxandrew]

Maybe I don't fully understand the problem. I assume that objective is to print rows integers maximum value. One can just:

with open('testname.txt', 'r') as f:
    header = next(f)
    for row in f:
        data = row.split()
        print(f"Maximum value on {data[0]}'s row is {max(data[1:], key=lambda x: int(x))}")

If row number instead of name needed one can use enumerate and start at appropriate number (is header row #1?).

This code will output:

Output:
Maximum value on mark's row is 50
Maximum value on teo's row is 60
Maximum value on jain's row is 70
Maximum value on lue's row is 80
Maximum value on hed's row is 40

EDIT:
It is also possible to split and assign names in one go. If appropriate names are used it can deliver better readability. Also no need for lambda, int can be called directly.

name, *values = row.split()      # name is string and values is list
print(f"Maximum value on {name}'s row is {max(values, key=int)}")

Thank you for your assistance.