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help with sending and receiving pics taken
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help with sending and receiving pics taken
#1
I am trying to send a few pics via socket from server to client.
I get this error on the client side, and I am not sure how to fix it.
Error:
Traceback (most recent call last): File "C:/Users/PycharmProjects/client-server/client.py", line 34, in <module> im = Image.open(fp) File "C:\Users\PycharmProjects\client-server\venv\lib\site-packages\PIL\Image.py", line 2818, in open raise IOError("cannot identify image file %r" % (filename if filename else fp)) OSError: cannot identify image file <_io.BufferedReader name='test.png'>
here are both of my codes
SERVER
import cv2
import time
import socket
import glob
import os

host =  "127.0.0.1"
port = 5000

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((host, port))
s.listen(5)
print("server started...")


path1 = (r"C:\Users\Desktop\opencvpics")


def readFileImages():
    st = os.path.join(path1, "*.png")
    print(st)
    return glob.glob(st)


list1=readFileImages()
print(list1, "list1......")
while True:
    c, addr = s.accept()
    print(f"connection from {addr} has been established !")
    c.send(bytes("welcome to the server".encode()))

    for pics in list1:
        f=open(pics, 'rb')
        while True:
            veri=f.read()
            if not veri:
                break
            s.send(veri)
        f.close()

data = s.recv(4096)
data_arr = pickle.loads(data)

newrow = numpy.asarray(data_arr)
myoutput = numpy.vstack([myoutput, newrow])

s.close()
import socket

from PIL import Image

import pickle


host =  "127.0.0.1"
port = 5000

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host, port))



msg=s.recv(1024)
print(msg.decode())

fname="test.png"

fp = open(fname,'rb')

 # image
while True:

    strng = s.recv(1024)
    if not strng:
        break
    fp.write(strng)




im = Image.open(fp)

T= im.size
data=pickle.dumps(T)
s.send(data)
fp.close()
In the client code, I tried to move 'fp.close()'before 'im=Image.open(fp)' but it would then complain about dealing with a closed file.
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#2
Ignore this post, refer to this instead:
https://python-forum.io/Thread-send-a-few-pictures
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#3
I kept working on the code and changed a few lines.
Now I get no error, however, it looks like that the client is not fully executed,
in other words, I should be able to see these two statements being printed on the last lines
print('Successfully get the file')

print('connection closed')
but I don't. What exactly is stopping it?

Here is my edited code for serve and client.

SERVER
import cv2
import time
import socket
import glob
import os

host =  "127.0.0.1"
port = 5000

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((host, port))
s.listen(5)
print("server started...")


path1 = (r"C:\Users\Desktop\opencvpics")


def readFileImages():
    st = os.path.join(path1, "*.png")
    print(st)
    return glob.glob(st)


list1=readFileImages()
print(list1, "list1......")
while True:
    c, addr = s.accept()
    print(f"connection from {addr} has been established !")
    c.send(bytes("welcome to the server".encode()))

    for pics in list1:
        f=open(pics, 'rb')
        l = f.read(1024)
        while(l):
            c.send(l)
            print('Sent ', repr(l))
            l = f.read(1024)
        f.close()

        print('Done sending')
        c.send('Thank you for connecting'.encode())
CLIENT
import socket

from PIL import Image

import pickle


host =  "127.0.0.1"
port = 5000

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host, port))

s.send('Hello server!'.encode())

with open('received_file.png', 'wb') as f:
    print('file is open')

    while True:
        print('receiving data...')
        data = s.recv(1024)
        print('data=%s', data)



print('Successfully get the file')

s.close()
print('connection closed')
By the way, this time I included my code into the code box as usual, but somehow it doesn't look like I did. I am not sure why.
In addition, only one picture is received, instead of all of them.
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#4
Starting a new thread on same subject is taboo see: https://python-forum.io/misc.php?action=help&hid=22
Reply
#5
sorry, I haven't thought about it.
Thanks for reminding me.

Can you actually please help me?
I have been stuck in this for awhile, :)

Can anyone help me ?
Reply
#6
I continued to work on it, by turning bytes back into images, and I am now getting an error on the client side,
even though the files seem to be transferred.
Error:
Traceback (most recent call last): File "C:/Users/PycharmProjects/client-server/client.py", line 31, in <module> img = Image.open(io.BytesIO(data)) File "C:\Users\\PycharmProjects\client-server\venv\lib\site-packages\PIL\Image.py", line 2818, in open raise IOError("cannot identify image file %r" % (filename if filename else fp)) OSError: cannot identify image file <_io.BytesIO object at 0x076EE450>
SERVER
import cv2
import time
import socket
import glob
import os

host = "127.0.0.1"
port = 5000

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((host, port))
s.listen(5)
print("server started...")

path1 = (r"C:\Users\Desktop\opencvpics")


def readFileImages():
    st = os.path.join(path1, "*.png")
    print(st)
    return glob.glob(st)


list1 = readFileImages()
print(list1, "list1......")
print(type(list1))

while True:
    c, addr = s.accept()
    print(f"connection from {addr} has been established !")
    c.send(bytes("welcome to the server".encode()))

    for pics in list1:
        f = open(pics, 'rb')
        l = f.read(1024000)
        while (l):
            c.send(l)
            print('Sent ', repr(l))
            l = f.read(1024)
        f.close()

        print('Done sending')
        c.send('Thank you for connecting'.encode())
CLIENT
import socket
import cv2

from PIL import Image
import io

import pickle


host =  "127.0.0.1"
port = 5000

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host, port))

s.send('Hello server!'.encode())

with open('received_file.png', 'wb') as f:
    print('file is open')

    #while f:
    print('receiving data...')
    data = s.recv(1024)
    print('data=%s', data, "ASDFASDSADFASDFVSSDSAFSADDFDSAFD")
    f.write(data)
    print('Successfully get the files')

    print('connection closed')
    print(type(data))
    print(len(data))
    img = Image.open(io.BytesIO(data))
    img.show()

s.close()
P.S.
The directory in the client contains a few images, and I desire to send them all to the client.
Reply
#7
this is not something I would do very often, but here's a link to an example: https://stackoverflow.com/a/42534868
Reply
#8
can you or anyone actually figure out what is the mistake in the last code I posted?
I was already aware of that link, but I need to see how "multiple" images are sent to the client (not from).
Reply
#9
I noticed that the loop in line 33 on the server code only takes the first picture, when I thought it would iterate through the entire list, how so? how to fix it ?

these lines alone

path1 = (r"C:\Users\Desktop\opencvpics")

def readFileImages():
    st = os.path.join(path1, "*.png")
    print(st)
    return glob.glob(st)

for i in readFileImages()[:]:
    f=open(i, 'rb')
    l=f.read()
    print(len(l))
iterate as many times as the length of the list, but these same lines implemented in the server code above, stop after the first iteration. Why ?
Reply
#10
Doesn't anyone know how to help me?
I am not asking anything too demanding.
Let me know if there are any problems in my way of asking,
so I can rearrange.
Reply


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