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 how to calculate overlaping coefficient between two probablity functions Staph Silly Frenchman Posts: 32 Threads: 17 Joined: May 2019 Reputation: 0 Likes received: 0 #1 Aug-10-2019, 05:02 AM I have two probability density functions generated as follows: location = 0.97 scale = 1.0 x = np.linspace(-5,5,100) plt.subplots(figsize=(12,4)) pdf1 = skew_norm_pdf(x,location,scale,SKEW_PARAMS[0]) pdf2 = skew_norm_pdf(x, location, scale, SKEW_PARAMS[1] How can I calculate the overlapping coefficient between the two generated probability density funtions? Gribouillis Posts: 2,132 Threads: 20 Joined: Jan 2018 Reputation: 201 Likes received: 513 #2 Aug-10-2019, 07:29 AM In theory you can do it by finding the places where the pdfs intersect, then use the cdf. For example if pdf1(x) < pdf2(x) for all x in an interval (a, b) then you can add cdf1(b) - cdf1(a) to the overlapping coefficient. Staph Silly Frenchman Posts: 32 Threads: 17 Joined: May 2019 Reputation: 0 Likes received: 0 #3 Aug-11-2019, 12:49 AM Hi can you please explain this further, will be nice if you could add some simple scrip to do this? Moreover how do I know pdf1(x) < pdf2(x)? Staph Silly Frenchman Posts: 32 Threads: 17 Joined: May 2019 Reputation: 0 Likes received: 0 #4 Aug-11-2019, 08:10 AM (This post was last modified: Aug-11-2019, 10:33 AM by scidam. Edited 2 times in total. Edit Reason: tags added ) How can I find the overlap between the following distributions? ```from import scipy.stats np.random.seed(seed=233423) R1 = scipy.stats.skewnorm(2, 0, 2).rvs(1000) R2 = scipy.stats.skewnorm(3, 1, 2).rvs(1000) ```how to find the overlap between R1 and R2 in python? These are two randomly generated distributions buran wrote Aug-11-2019, 08:15 AM:lease post all code, output and errors (in it's entirety) between their respective tags. Refer to BBCode help topic on how. Use the "Preview Post" button to make sure the code is presented as you expect before hitting the "Post Reply/Thread" button. Please, don't start new threads unnecessarily. « Next Oldest | Next Newest »

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