iloc

[d8a988]

in pandas, in order to obtain the 8th row from the 4th to the 7th column,
the following command works properly:

(data.iloc[9, 5:8] )

but what if I would like to repeat the same operation for other specific rows,
for instance the 15th, the 18th and so on, is there anything that I can implement
in the line of code above or I must write data.iloc for every row that I am interested in?

[anbu23]

data.iloc[[9,15,18], [5:8]] 

[d8a988]

your line produces an error:

Error:
 File "C:/Users/file.py", line 11
    print(data.iloc[[9,15,18], [5:8]])
                                 ^
SyntaxError: invalid syntax

[d8a988]

I have tried another strategy but it doesn't always work:

the for loop itself prints all the lines the right way, (I am converting them to lists)

    for i in range(9,100,18):
        return(( (data.iloc[i,2:10]).values.tolist()  ))

but inside a function, only the first list is printed.
How come? How to fix this function in order to obtain
the same outcome as the for loop?

def total_lists(start, end, step):
    for i in range(start,end,step):
        return(( (data.iloc[i,2:10]).values.tolist()  ))

print(total_lists(9,100,18)) # just prints the first line

[anbu23]

Return will exit function on the first row. Try like this

def total_lists(start, end, step):
    lst = []
    for i in range(start,end,step):
        lst.append(data.iloc[i,2:10]).values.tolist())
    return(lst)

[d8a988]

same thing. Only the first line is printed.

[anbu23]

same thing. Only the first line is printed.

Can you post complete code?

[d8a988]

That's ok, I figured out another way.
All you need to do is to convert it to a list
outside the function.