'int' object does not support item assignment

[shane1236]

Can someone correct that kind of error?

def new(app):
    app=0
    for i in range(10):
      app[i]=i+1
      print(app)

[buran]

Can someone correct that kind of error?

In order to fix it, one need to know what expected output is. Currently that One is just you.

[epokw]

You initialized app as an integer in app=0. Later in the code you called app in app[i], which you can only do with list items and dictionaries, not integers.

I'm not 100% sure what you were trying to do, but if you want to create a list of numbers from 1 to 10, I would suggest initializing app as a list with app = [], and then using the .push() method to add items to the list.

I hope that helps!

[shane1236]

yes I want the same as you said can you just code it for me. Also it runs when I put app=[], however, it doesnot print anything can you look into that??

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I want the same as below post said, however, Also it runs when I put app=[], however, it doesnot print anything can you look into that??

[epokw]

yes I want the same as you said can you just code it for me. Also it runs when I put app=[], however, it doesnot print anything can you look into that??

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I want the same as below post said, however, Also it runs when I put app=[], however, it doesnot print anything can you look into that??

Sorry, I made a mistake. You should use the .append() method (not the .push() method, that is from JavaScript ).

Did you forget to call the function?

def new():
    app = []
    for i in range(10):
      app.append(i+1)
    print(app)

new()

I wouldn't have passed "app" in as a parameter to the function, as you did. I suspect you also meant to "print(app)" only once, instead of putting it inside the for loop.

By the way, this might be a bit more advanced, but for future reference, you can cut all those lines down to one by using a list comprehension as such:

app = [i for i in range(1, 11)]
print(app)

And that will give you the same output

[buran]

print(list(range(1,11)))