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list comprehension error
#1

hi. i am looking to create a list [10,0,10,0]. up to now i have the following code:
mylist=[10 if i%2==1 else 0 for i in range(1,5)]
the above returns [10,0,10,0]. Any ideas on how to fix that please?
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#2
Your goal
(Nov-04-2017, 06:03 PM)atux_null Wrote: i am looking to create a list [10,0,10,0]

the output of your script:
(Nov-04-2017, 06:03 PM)atux_null Wrote: the above returns [10,0,10,0]

what is the problem?
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#3
sorry, typo. i need to have [10,0,10,10]
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#4
what is the logic? because without underlying logic here it is:
mylist = [10, 0, 10, 10]
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#5
the logic is to have in the format:
mylist=[___for i in range(1,5)]
where ___ needs to get substituted from the necessary part of the code to make the list have [10,0,10,10]
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#6
againĀ  what is the logic -how you decide 10 or 0?
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#7
10 if the number is odd else 1?
"As they say in Mexico 'dosvidaniya'. That makes two vidaniyas."
https://freedns.afraid.org
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#8
the code
10 if the number is odd else 1
? returns [10,1,10,1]
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#9
(Nov-04-2017, 08:03 PM)atux_null Wrote: the logic is to have in the format:
mylist=[___for i in range(1,5)]
where ___ needs to get substituted from the necessary part of the code to make the list have [10,0,10,10]
Well, I mean:
>>> [0 if i == 2 else 10 for i in range(1,5)]
[10, 0, 10, 10]
>>>
Seems to get what you want, but I've got to say that is a really stupid problem.
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