##### norm
 norm mcgrim Spam, spam, eggs, and spam Posts: 203 Threads: 41 Joined: Mar 2019 Reputation: 0 Mar-21-2019, 10:00 AM (This post was last modified: Mar-21-2019, 10:34 AM by mcgrim.) I am writing a program that takes a vector as parameter and returns the corresponding normalized vector. The first part of the program attempts this task manually (without the function 'norm') and the second part is with the 'norm' function. I have written them both and the program runs but I cannot understand why I get different outcomes. I get 1.06 in the fist part and 3.74 in the second. why? (both parts are separated by #------------------------------------) ```import numpy as np from numpy import array from scipy.linalg import norm """ V=[1,2,3] n_vec=sqrt(V[0]**2+V[1]**2+V[2]**3) def v_vector(V): return ((V[0]/n_vec)+(V[1]/n_vec)+(V[2]/n_vec)) print(v_vector(V)) """ #----------------------------------------------------------- V=[1,2,3] def v_vector(V): return (linalg.norm(V)) print(v_vector(V))``` I solved this issue myself, but I am not sure how to remove this post. Reply nilamo Last Thursdayist Posts: 3,290 Threads: 94 Joined: Sep 2016 Reputation: 138 Mar-21-2019, 07:05 PM So what was the solution? Reply mcgrim Spam, spam, eggs, and spam Posts: 203 Threads: 41 Joined: Mar 2019 Reputation: 0 Mar-22-2019, 12:39 PM the second step is actually correct but incomplete as it merely calculated the norm instead of the whole unit vector. Reply

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