print a word after specific word search

[evilcode1]

hello all ...
i have this string :

<?xml version="1.0" encoding="utf-8"?>
<metafile version="3.6" client="site">
<name>English (en-GB)</name>
<version>3.6.0</version>
<creationDate>July 2016</creationDate>
<author>Joomla! Project</author>
<authorEmail>admin@joomla.org</authorEmail>
<authorUrl>www.joomla.org</authorUrl>
<copyright>Copyright © 2005 - 2016 Open Source Matters. All rights reserved.</copyright>
<license>GNU General Public License version 2 or later; see LICENSE.txt</license>
<description>en-GB site language</description>
<metadata>
<name>English (en-GB)</name>
<tag>en-GB</tag>
<rtl>0</rtl>
<locale>en_GB.utf8, en_GB.UTF-8, en_GB, eng_GB, en, english, english-uk, uk, gbr, britain, england, great britain, uk, united kingdom, united-kingdom</locale>
<firstDay>0</firstDay>
<weekEnd>0,6</weekEnd>
</metadata>
<params />
</metafile>

i need to search for <version> then print just ( 3.6.0 ) , how i can do that ?

[buran]

what have you tried?

[evilcode1]

what have you tried?

match = re.compile(r'"<version>"\:(".*?)["\[]')
a = match.findall(q)
print(a)

i got

Output:
[]

[buran]

https://docs.python.org/3.7/library/xml....ttree.html

or use some external module as lxml or BeautifulSoup

[newbieAuggie2019]

i have this string :

<?xml version="1.0" encoding="utf-8"?>
<metafile version="3.6" client="site">
<name>English (en-GB)</name>
<version>3.6.0</version>
<creationDate>July 2016</creationDate>
<author>Joomla! Project</author>
[ ... ]

i need to search for <version> then print just ( 3.6.0 ) , how i can do that ?

Hi!

Maybe you could use something like:

import re

string1 = '''<?xml version="1.0" encoding="utf-8"?>
<metafile version="3.6" client="site">
<name>English (en-GB)</name>
<version>3.6.0</version>
<creationDate>July 2016</creationDate>
<author>Joomla! Project</author>
[ ... ]'''
requirement1 = re.search('<version>(.*)</version>', string1)
print(requirement1.group(1))

that produces the following output:

Output:
3.6.0

All the best,

[evilcode1]

i have this string :

i need to search for <version> then print just ( 3.6.0 ) , how i can do that ?

Hi!

Maybe you could use something like:

import re

string1 = '''<?xml version="1.0" encoding="utf-8"?>
<metafile version="3.6" client="site">
<name>English (en-GB)</name>
<version>3.6.0</version>
<creationDate>July 2016</creationDate>
<author>Joomla! Project</author>
[ ... ]'''
requirement1 = re.search('<version>(.*)</version>', string1)
print(requirement1.group(1))

that produces the following output:

Output:
3.6.0

All the best,

thank u very much <3 works and this is better than starting coding new code with xml.etree.ElementTree

---

https://docs.python.org/3.7/library/xml....ttree.html

or use some external module as lxml or BeautifulSoup

thank u for quick response , but i will prefer regex and @newbieAuggie2019 give me a solution

[newbieAuggie2019]

thank u very much <3 works

You're welcome!

[buran]

why not parse html/xml with regex is discussed so many times... use proper tools for the task or it will bite you when you don't expect

[newbieAuggie2019]

https://docs.python.org/3.7/library/xml....ttree.html

or use some external module as lxml or BeautifulSoup

thank u for quick response , but i will prefer regex

why not parse html/xml with regex is discussed so many times... use proper tools for the task or it will bite you when you don't expect

Hi again!

Although I always try to address a problem from the point of view and knowledge of a newbie like myself, if anyone from this site advises not to use what I have suggested in good faith, I would take their advice into consideration, as their knowledge is much much deeper than mine.

All the best,