read python and php from a file and copy them to their own files to execute

[Myersj281]

I have this function here to read python and php from a single script and create a file for each and paste their code into them accordingly. Execution is a seperate function.



The tested mixed source looks like this: (the php echo statements are equivelent to pythons print and not relevent to this issue.)

?>
print("python check 1")
<?php
echo "php check 1";
?>
print("python check 2")
<?php
echo "php check 2";
?>

The python function to "compile" this:

from sys import argv
from  subprocess import call
import os

def split():
 code, ext = os.path.splitext(argv[1])
 source = code + ext
 phpexec = code + ".php"
 pyexec = code + ".py"
 with open(source, "r") as source:
  if ext != ".pyp":
   print("Source file has an invalid file extension! It must end with .pyp.")
  else:
   with open(phpexec, "a+") as phpexec:
    if ext == ".pyp":
     for line in source:
      if line.strip() == "<?php":
       copy = True
      elif line.strip() == "?>":
       copy = False
      elif copy:
       start = line.find("<?php") + 1
       end = line.find("?>", start)
       lines = line[start:end]
       print(lines, file=phpexec)
   with open(pyexec, "a+") as pyfile:
    for line in source:
     if line.strip() == "?>":
      copy = True
     elif line.strip() == "<?php":
      copy = False
     elif copy:
      print("#!/usr/bin/env python", file=pyfile)
      print(lines, file=pyfile) 

The python isn't written to it's file and the php is returning the entire line which leads me to believe it's not running and python or my terminal is printing the entire lines:

echo "php check 1";
echo "php check 2";

The function above is meant to check for the "<?php" and "?>" tags to locate the php and seperate it from python. Where is my problem? Should I be openning the files differently or maybe how I'm writing to them?

[ichabod801]

I think you want to print line to pyfile on line 34, not lines. I would also write the shebang to the file (line 33) before the for loop, not during it. You just want it at the top, not before every line.

Also, I would use pyfile.write(line). It's more pythonic. Using print makes your code rather confusing.

[Myersj281]

ok so i changed lines to line (i had a start=/end= for python too but edited it out trying to debug)
and moved the shebang just above the for loop and the "compiled" python file now has a shebang but thats it and the php is still the same

EDIT: after changing the prints to writes its not automatically going to the next line. how can i get that back while still using write?

[ichabod801]

Adding \n to the end of the shebang literal should fix the problem with the next line.

For the php section, the elif copy block triggers on the line after '<?php'. Then you look for '<?php' and '?>', neither of which exist on that line. So it ends up writing an empty string to the phpexec file. You would want to make it more like the python section. If you want to keep the php tags in the php file, write them when you detect them and change the copy flag.

[Myersj281]

ok so both open blocks look like this:

   with open(pyexec, "a+") as pyfile:
    pyfile.write("#!/usr/bin/env python")
    for line in source:
     if line.strip() == "?>":
      copy = True
     elif line.strip() == "<?php":
      copy = False
     elif copy:
      pyfile.write(line)

php is written to it's file properly but not executed like it should be and pythons file just get the shebang but if i write to it manually it does run. EDIT: the php block is now outputing:

php check 1
php check 2

like it should. The biggest issue is python not writing it lines

[ichabod801]

Like I said, the shebang needs a \n at the end of it to write to a new line. The lines you are reading in from source should be read in with a terminal \n, so they should write out fine. They're writing out fine for me.

I don't know about executing php, I'm a Python programmer.

[Myersj281]

I don't know about executing php, I'm a Python programmer.

the php is fine now the python just isnt writing out to its file

[ichabod801]

Can you repost your code and input as it is now?

[Myersj281]

I have made a small modification that does nothing for the issue but allows me to use a browser for a gui. Basicaly the php block is now html wich contains php. Here's my entire source:

#!/bin/env python
from sys import argv
from  subprocess import call
import os

def split():
 code, ext = os.path.splitext(argv[1])
 source = code + ext
 phpexec = code + ".php"
 pyexec = code + ".py"
 with open(source, "r") as source:
  if ext != ".pyp":
   print("Source file has an invalid file extension! It must end with .pyp.")
  else:
   with open("./index.php", "a+") as phpexec:
    if ext == ".pyp":
     phpexec.write("<html>\n")
     for line in source:
      if line.strip() == "<html>":
       copy = True
      elif line.strip() == "</html>":
       copy = False
      elif copy:
       phpexec.write(line)
     phpexec.write("</html>")
   with open(pyexec, "a+") as pyfile:
    pyfile.write("#!/usr/bin/env python\n")
    for line in source:
     if line.strip() == "</html>":
      copy = True
     elif line.strip() == "<html>":
      copy = False
     elif copy:
      pyfile.write(line)
      
      
def exe():
 code, ext = os.path.splitext(argv[1])
 #i was calling the python script from here but it now needs to be in the php so it can get phps variables. php already gets pythons variable through the "requests" module.
 php = ["php","-S" , "127.0.0.1:1270"]
 call(php)
 

split()
exe()

and the test .pyp file:

</html>
print("python check 1")
<html>
 <?php
  echo "php check 1<br>";
  ?>
 </html>
print("python check 2")
<html>
 <?php
  echo "php check 2<br>"; #the <br> is an html line break. it's equivelant to a \n but works in a browser.
  ?>
</html>

[ichabod801]

I'm not having any problems with the python, it's writing to the file fine.