rock,paper,scissors

[Jei]

I need to make this classic game.
my problem is that i dont know how to compare them to each other.

maybe something like this?

if user1 = rock and user2 = rock:
   print()
if user1 = rock and user2 = paper
   print()
#etc 
#etc

or is there a faster way?

[Yoriz]

Comparison is done by double ==, assignment is one =

[Jei]

Comparison is done by double ==, assignment is one =

ha yeah i know that, i made a typo, my bad

so the only way to make this work is to == all of them?

[stranac]

Yeah, making a few comparisons is probably the simplest way to go.
Do note that a simple user1 == user2 can be used to check for a draw.

[ichabod801]

There are other ways to do it. One is to make a dictionary:

wins = {'rock': 'scissors', 'scissors': 'paper', 'paper': 'rock'}

Then you just need to test three things: if it matches the dictionary it's a win, if they played the same thing it's a draw, otherwise it's a loss.

[Yoriz]

You could use

if (user1, user2) == ('rock', 'rock'):

[Jei]

Done!   how would you have done it?

import random


def sub(computer):
    if computer == 1:
        computer = "Foot"        
    elif computer == 2:
        computer = "Nuke"
    elif computer == 3:
        computer = "Cockroach"
    print("Computer chose: ",computer)
    
    

def main():
    wins = 0
    rounds = 0
    draws = 0
    
    
    while True:
        computer = random.randint(1,3)
        player = input("Foot, Nuke or Cockroach? (Quit ends): ")
        
        if player == "Quit":
            print("You played",rounds, "rounds, and won",wins,"rounds, playing tie in",draws,"rounds.")
            break
        elif player == ("Spaceshuttle"):
            print("Incorrect selection.")
        else:
            print("You chose: ", player)
            sub(computer)
            rounds += 1
        
            if (player, computer) == ("Foot", 1):
                draws += 1
                print("It is a tie!")
            elif (player, computer) == ("Foot", 2):
                print("You LOSE!")
            elif (player, computer) == ("Foot", 3):
                wins += 1
                print("You WIN!")
            elif (player, computer) == ("Nuke", 2):
                print("both loose")
            elif (player, computer) == ("Nuke", 1):
                wins += 1
                print("You WIN!")
            elif (player, computer) == ("Nuke", 3):
                print("You LOSE!")
            elif (player, computer) == ("Cockroach", 1):
                print("You LOSE!")
            elif (player, computer) == ("Cockroach", 2):
                wins += 1
                print("You WIN!")
            elif (player, computer) == ("Cockroach", 3):
                draws += 1
                print("It is a tie!")
            
        
        
        
        
        

if __name__ == "__main__":
        wins = 0
        rounds = 0
        draws = 0
        main()
        

[Kebap]

how would you have done it?

if __name__ == "__main__":
        wins = 0
        rounds = 0
        draws = 0
        main()

Those 3 lines can be omitted, they follow inside main() anyway.

[ichabod801]

You could also take out the sub function and the call to the sub function. They're not doing anything since you don't return anything from sub to the main function.

[Kebap]

They're not doing anything since you don't return anything

Sub is used for printing :)

@Jei: How do you handle wrong input by the user? Maybe they had a typo