search and replace with line in document

[chickflick91]

I am trying to write a code that searches and replaces with a line in the document. i have:

import re
x = open(r'F:\1\xxx.txt')
string = open(r'F:\1\xxx.txt').read()
Lines = x.readlines()
new_str = re.sub('zzz1', (Lines[0]) , string)

open(r'F:\1\xxx2.txt', 'w').write(new_str)

in xxx1 document i have written for testing:
1
2
3
4
5
6
7
8
9
10
zzz1
11

but the output I get in xxx2 document is:
1
2
3
4
5
6
7
8
9
10
1

11

can i have zzz1 replaced without the empty line to follow?
and how can i do it again say if wanting to replace a zzz2 with line 2?

[micseydel]

For the first question: yes. Instead of

new_str = re.sub('zzz1', (Lines[0]) , string)

you can do

new_str = re.sub('zzz1', Lines[0].strip() , string)

For the second question - what have you tried?

[chickflick91]

working solution:

import re
x = open(r'F:\1\xxx.txt')
Lines = x.readlines()


repldict = {'zzz1':(Lines[0]).strip(), 'zzz2':(Lines[1]).strip()}
def replfunc(match):
return repldict[match.group(0)]

regex = re.compile('|'.join(re.escape(x) for x in repldict))
with open(r'F:\1\xxx.txt') as fin, open(r'F:\1\xxx2.txt','w') as fout:
for line in fin:
fout.write(regex.sub(replfunc,line))