Dec-22-2017, 02:12 PM
Hello everyone, I'm a newbie to Python programming and I've really fallen in love with the language; although I've got some little qualms right now.
While reading the book "Violent Python A Cookbook for Hackers, Forensic Analysts, Penetration Testers and Security Engineers", I came across this piece of code:
import socket socket.setdefaulttimeout(2) s = socket.socket() s.connect(("192.168.95.148",21)) ans = s.recv(1024) print ansWhen I typed it into the python console on Unix: I got this error message:
Error:Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/socket.py", line 228, in meth
return getattr(self._sock,name)(*args)
socket.timeout: timed out
So I carried out some research online for a solution or an explanation to what is going on. But I didn't find any that was convincing. For example, I were asked to modify that code to look like this: import socket try: s = socket.socket() s.settimeout(10) s.connect((192.168.95.148", 21)) ans = s.recv(1024) print ans s.shutdown(1) s.close() except socket.error as socketerror: print("Error: ", socketerror) except socket.timeout: print("NO RESPONSE")After running that one, I get this other error message:
Error:('Error: ', timeout('timed out',))
So, please if anyone could explain what this error messages actually mean and help me understand how I could fix that, I would be very grateful.