sorting list

[arian29]

Why does print(listA.sort()) return None ? But if I sort first and then print(listA), returns the sorted list items.

listA=[1,2,3,9,8,7,6]
print(listA[1])
print(listA.sort())

[ibreeden]

Yes you are right. One might expect a sorted list is returned, but look at the definition of list.sort. It says:

This method sorts the list in place

. Apparently this means the list is sorted by this method. But it returns nothing.

>>> listA=[1,2,3,9,8,7,6]
>>> print(listA.sort())
None
>>> print(listA)
[1, 2, 3, 6, 7, 8, 9]

[ndc85430]

That's what "in place" means - the original list is mutated, so there's nothing to return. sorted on the other hand will return a new, sorted list.