[split] Single slash syntax in file path

[aogata]

I am having a similar noob problem.

Setup:
I'm calling the python script with arguments from a different program through the command prompt (this other program does not offer full python integration)
This other program collects a file path, turns it into a string variable and passes it to the python script through an argument
The original path comes with a single slash syntax. The python script wants it as a double slash syntax, but I don't know how to convert it.

any help would be appreciated

Here are my tests

import os
import re

s="C:\Users\alex.ogata\Desktop\test001"

encode=s.encode('unicode-escape')
#r1= re(s)
r2= repr(s)
r3= re.escape(s)
ospath = os.path.normpath(s)
st = str(s)
newStr=s.replace(chr(92),"\\")


print s
print encode
#print r1
print r2
print ospath
print st
print newStr

print "this is what I want" + r"C:\\Users\\alex.ogata\\Desktop\\test001"



this is the python script for reference

# these are the arguments coming int
scriptname, imagePathIn=argv

#this is not working
imagePath = re.escape(imagePathIn)


filenames = [f for f in listdir(imagePath) if isfile(join(imagePath, f))]
print(filenames)
print imagePath

def get_filepaths(directory):

file_paths =

for root, directories, files in os.walk(directory):
for filename in files:
# Join the two strings in order to form the full filepath.
filepath = os.path.join(root, filename)
file_paths.append(filepath) # Add it to the list.

return file_paths
fileList= get_filepaths (imagePath)

User has been warned for this post. Reason: Hijack thread, no BBcode

[snippsat]

Your code is without indentation.
This is wrong,escape character will give errror.
s="C:\Users\alex.ogata\Desktop\test001"
For file path in Windows always use:

>>> s = r"C:\Users\alex.ogata\Desktop\test001"
>>> s
'C:\\Users\\alex.ogata\\Desktop\\test001'
>>> # or 
>>> s = "C:/Users/alex.ogata/Desktop/test001"
>>> s
'C:/Users/alex.ogata/Desktop/test001'
>>> # or 
>>> s = "C:\\Users\\alex.ogata\\Desktop\\test001"
>>> s
'C:\\Users\\alex.ogata\\Desktop\\test001'

[aogata]

Thank you, I should have clarified
The string s="C:\Users\alex.ogata\Desktop\test001" is something I am receiving into the python script as a given
it is coming in as a variable called imagePathIn

I'm looking to convert it into 'C:\\Users\\alex.ogata\\Desktop\\test001'

As the previous response showed, you can do: r"C:\Users\alex.ogata\Desktop\test001"
But how do you do that by using the variable imagePathIn and not the original string?

You code is without indentation.
This is wrong,escape character will give errror.
s="C:\Users\alex.ogata\Desktop\test001"
For file path in Windows always use:

>>> s = r"C:\Users\alex.ogata\Desktop\test001"
>>> s
'C:\\Users\\alex.ogata\\Desktop\\test001'
>>> # or 
>>> s = "C:/Users/alex.ogata/Desktop/test001"
>>> s
'C:/Users/alex.ogata/Desktop/test001'
>>> # or 
>>> s = "C:\\Users\\alex.ogata\\Desktop\\test001"
>>> s
'C:\\Users\\alex.ogata\\Desktop\\test001'

[snippsat]

it is coming in as a variable called imagePathIn I'm looking to convert it into 'C:\\Users\\alex.ogata\\Desktop\\test001'

You should get(\\) from command line.
Test:

import sys

print 'List: {}'.format(sys.argv)
#  print will only show \
print 'File name {}'.format(sys.argv[1])
# This is what you getting using repl
print 'File name {!r}'.format(sys.argv[1])

Output:
C:\1
λ py -2.7 f.py C:\Users\alex.ogata\Desktop\test001
List: ['f.py', 'C:\\Users\\alex.ogata\\Desktop\\test001']
File name C:\Users\alex.ogata\Desktop\test001
File name 'C:\\Users\\alex.ogata\\Desktop\\test001'