Python Forum
win32com Trying to open a xlmb file with macros
Thread Rating:
  • 2 Vote(s) - 4 Average
  • 1
  • 2
  • 3
  • 4
  • 5
win32com Trying to open a xlmb file with macros
#1
Hi guys, I am trying to read data from a xlsb file using the code below
import win32com.client
excel = win32com.client.Dispatch("Excel.Application")
excel.DisplayAlerts = False
excel.Visible=False
#doc1 = excel.Workbooks.Open.
doc = excel.Workbooks.Open("O:\xxx\xxx\xxx.xlsb")
doc.SaveAs(Filename="O:\\xxx\\xxx\\xxx.csv",FileFormat=6)
doc.Close()
excel.Quit()
The problem is that it does appear a mask with
Error:
RunTimeError '1004' Cannot Run the macro....
Is there any way just to read the data in Excel without the need to run any macro?

Thanks
Reply
#2
Use code tag,i have added in your post.
win32com is now very little used for excel connection,now is XLSB a binary Microsoft Excel format.
There is a library for this pyxlsb that read XLSB.
Then can also read into pandas,for greater power if need edit.
Common Excel Tasks Demonstrated in Pandas
import pandas as pd
from pyxlsb import open_workbook as open_xlsb

df = []

with open_xlsb('some.xlsb') as wb:
    with wb.get_sheet(1) as sheet:
        for row in sheet.rows():
            df.append([item.v for item in row])

df = pd.DataFrame(df[1:], columns=df[0])
Reply
#3
Thanks a lot snippsat,I am an absolute beginner, only working in Python in a week.
However, I changed the file to xlsm and now I am using xlrd

import xlrd
file_location='O:\xxx\xxxx\xxx Python.xlsm'
workbook = xlrd.open_workbook(file_location)
sheet = workbook.sheet_by_index(1)
sheet.cell_value(0,0)
sheet.nrows
sheet.ncols
for col in range(sheet.ncols):
print (sheet.cell_value(3, col))

It's reading the data without triggering the macro, but now I need to write the data to a csv file and struggling to understand how using the for. Is there a way to give a range to set a loop in print (sheet.cell_value(3, col)) and to use a variable instead of print?

Many Thanks
Reply
#4
Hi guys, I am now using the code below:
import xlrd
file_location='O:\xxx\xxxxxx\xxx.xlsm'
workbook = xlrd.open_workbook(file_location)
#sheet = workbook.sheet_by_index(2)
xl_sheet =workbook.sheet_by_name("B Data")

for rownum in range(xl_sheet.nrows):
print (xl_sheet.row_values(rownum))

It reads the data from an Excel file which uses a third part add in that update the data. The point is that I only see the original data but not the updated. Let's say that the Cell 1 Col A has 20 as value, this is what Python shows me. Now, if I see the file on the machine with the plug in installed the value is 22 but the code in Python still shows me 20. Any idea how can I set a process to see the data when it is changed and not only the original one?

Thanks
Reply


Possibly Related Threads…
Thread Author Replies Views Last Post
  Open/save file on Android frohr 0 316 Jan-24-2024, 06:28 PM
Last Post: frohr
  file open "file not found error" shanoger 8 1,087 Dec-14-2023, 08:03 AM
Last Post: shanoger
  How can i combine these two functions so i only open the file once? cubangt 4 852 Aug-14-2023, 05:04 PM
Last Post: snippsat
  I cannot able open a file in python ? ted 5 3,300 Feb-11-2023, 02:38 AM
Last Post: ted
  testing an open file Skaperen 7 1,375 Dec-20-2022, 02:19 AM
Last Post: Skaperen
  I get an FileNotFouerror while try to open(file,"rt"). My goal is to replace str decoded 1 1,400 May-06-2022, 01:44 PM
Last Post: Larz60+
  Dynamic File Name to a shared folder with open command in python sjcsvatt 9 6,025 Jan-07-2022, 04:55 PM
Last Post: bowlofred
  win32com — How to resolve “AttributeError: xlUp” for Excel files? JaneTan 2 4,216 Aug-18-2021, 05:27 AM
Last Post: snippsat
Exclamation win32com: How to pass a reference object into a COM server class Alfalfa 3 4,865 Jul-26-2021, 06:25 PM
Last Post: Alfalfa
  Open an excel file Newbie1114 1 2,336 Jun-16-2021, 09:11 PM
Last Post: Gribouillis

Forum Jump:

User Panel Messages

Announcements
Announcement #1 8/1/2020
Announcement #2 8/2/2020
Announcement #3 8/6/2020