Python Forum

Hi guys,

Trying to a simple match with a variable input.

* list1['30 dfa00','NOPE 223123','41 53452','XX 123453','342']
* variable ...could be anything.

Basicly it should do something like:
if list1 starts with variable: remove those characters, return the rest of the string else return full string.

import re
# the variable is ALWAYS [number][number][space]
#
prog = re.compile('(0-9)+( )')
list1=['30 dfa00','NOPE 223123','41 53452','XX 123453','342']
output=[]
for l in list1:
	if prog.match(l):
		output.append(l.split(3)[1])
	else:
		output.append(l)
	
print(output)
#should return
#dfa00, NOPE 223123, 53452, XX 123453, 342

What am I doing wrong?

import re
# the variable is ALWAYS [number][number][space]
#
prog = re.compile("([0-9]+)+( )")
list1=['30 dfa00','NOPE 223123','41 53452','XX 123453','342']
output=[]
for l in list1:
    if prog.match(l):
        output.append(l.split(3:))
    else:
        output.append(l)
     
print(output)
#should return
#dfa00, NOPE 223123, 53452, XX 123453, 342

Hmmm this is what I have now ... and it seems to work. Good approach?

prog = re.compile("[0-9]+ ")

And for just two numbers:

prog = re.compile("[0-9]{2} ")

(Jul-03-2018, 03:34 PM)gontajones Wrote: [ -> ]
prog = re.compile("[0-9]+ ")
And for just two numbers:
prog = re.compile("[0-9]{2} ")

@gontajones, thanks for your feedback! Learned something from it.

Just for my understanding... Since I'm trying to do something with the first characters of a string (and only those) ... I read that using the "^" triggers the beginning of the string (and neglecting the rest).

If a string would be "sometextandnumbers 44 otherthingstoo" to my understanding my current re.compile should return 'etextandnumbers 44 otherthingstoo' .... but it doesn't (returns full string). So adding the '^' would be unnecessary but feels unnatural.

Your 50 cents on this?

I test all my regex here Regex101.
Try it by yourself and you'll learn a lot.

^ = for the start of the regex
$ = for the end

What is your current re.compile()?
What do you want to get from "sometextandnumbers 44 otherthingstoo"? The 44?
Just use the " " as limiters. Like ( [0-9]+ ).

Instead of trying to split string after the match,let regex to the whole job with re.sub().

>>> import re
>>> 
>>> list1 = ['30 dfa00','NOPE 223123','41 53452','XX 123453','342']
>>> output = []
>>> for item in list1:
...     output.append(re.sub(r'^\d{2}\s', '', item))
...     
>>> output
['dfa00', 'NOPE 223123', '53452', 'XX 123453', '342']

Thanks both for your helpfull insight!

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gontajones

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gontajones

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