Dec-08-2016, 03:32 PM
Python doesn't like it when I ask it things like, (-6)**(1/3). I can at least get some answer by changing it to (-6+0j)**(1/3), and it gives me a complex answer, but that's not quite complete, because in the complex plane, numbers have three cube roots. I can get multiple roots using [mpmath.root(a,b,k) for k in range(b)] (returning a**(1/b)), but that only works for whole-number roots, rather than arbitrary real exponents.
Is there a function out there somewhere that can give me every solution to an arbitrary a**b? I already use Sympy, so it would be great if it could work symbolically to give exact answers.
Is there a function out there somewhere that can give me every solution to an arbitrary a**b? I already use Sympy, so it would be great if it could work symbolically to give exact answers.