Python Forum

(Sep-16-2018, 11:51 AM)Windspar Wrote: [ -> ]...
'{0:0>6}\n'
{
0 = first variable
...

That has been redundant in most cases after 2.6 - unless you print a list/tuple and want to use selected elements and/or change the order of elements.

Thanks volcano63,

I also try with a for instruction but now an invalid syntax in line 10,

def add_zero(nbr: str, m: int = 6) -> str:
    return "0" * (m - len(nbr)) + nbr
 
with open("dico2.txt","w") as f:
    for a in range(999999):
        if a <= 99999:
            num_str = add_zero(str(a))
        else:
            num_str = str(a)
        f.write(num_str '\n')
        a += 1

Anybody, can this code run just changing syntax in line 10?

You missed the +

I didn't mean just add '\n'

I meant you need to use concatenation:

string + string

In this case one string comes from a variable the other from a literal string, namely '\n'

Ty gruntfutuk, ty all,

It works now.